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3 years ago

What measure of center should Mr. Malloy use for Amo and for Javier for the best possible grade?

2 answers:

7 0

The answer to this question is the first item in the choices which is "The teacher should use the mean for both Amo and Javier" when computing and comparing their grades. The mean is the average grade while the median is the center of the grade. It would be wrong to apply median in computing their grades and it would be also wrong when the use two different methods when computing and comparing their grades.

Kay [80]3 years ago

6 0

Answer:

C. The teacher should use the median for Amo and the mean for Javier.

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Eleanor and Max used two rectangular pieces of plywood, placed end-to-end, to make a long rectangular stage for the school play.

Flauer [41]

Answer:the width of plywood = 6.25 feet wide or 6 1/4 feet wide

Step-by-step explanation:

Step 1

Area of a rectangular plywood = length x width

Area of Ist Plywood= 7 x w

Area of 2nd Plywood= 61/2 x w=6.5 xw

But Total Arae of trhe two Plywoods are = 84 3/8 square feet.

Therefore Our equation to solve the problem becomes

Area of Ist Plywood + Area of 2nd Plywood =84 3/8 square feet.

7w + 6.5w = 84 3/8

13.5w= 84 3/8

w = 84 3/8/13.5

675/8 / 13.5

w=6.25

Therefore the width of plywood = 6.25 feet wide or 6 1/4 feet.

3 0

3 years ago

Alan borrowed $570 for a new bed. He made 9 monthly payments to repay the loan. He

stepladder [879]

$~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\dotfill &\$45\\ P=\textit{original amount deposited}\dotfill & \$570\\ r=rate\to r\%\to \frac{r}{100}\\ t=months\dotfill &9 \end{cases} \\\\\\ 45 = (570)(\frac{r}{100})(9)\implies \cfrac{45}{(570)(9)}=\cfrac{r}{100}\implies \cfrac{1}{114}=\cfrac{r}{100} \\\\\\ \cfrac{100}{114}=r\implies \stackrel{\%}{0.88}\approx r$

4 0

1 year ago

(GIVING BRAINLIEST AND EXTRA POINTS!!!)

rosijanka [135]

Answer:0.65

Step-by-step explanation:

Firstly, we convert the fractions into decimals:

6/10=0.6

1/5=0.2

1/4=0.25

We then get : 0.6 - 0.2 + 0.25

0.6-0.2=0.4

0.4+0.25=0.65

4 0

2 years ago

A runner runs around a circular track. He completes one lap at a time of t = 269 s at a constant speed of v = 4.6 m/s. What is t

AURORKA [14]

Answer:

$\boxed{\text{197 m}}$

Step-by-step explanation:

The formula relating distance (d), speed (s), and time (t) is

d = st

1. Calculate the distance

d = 269 s × 4.6 m·s⁻¹ = 1240 m

2.Calculate the track radius

The distance travelled is the circumference of a circle

$\begin{array}{rcl}C & = & 2 \pi r\\1240 & = & 2 \pi r\\\\r & = & \dfrac{1240}{2 \pi }\\\\& = & 197\\\end{array}\\\text{The radius of the track is }\boxed{\textbf{197 m}}$

5 0

3 years ago

consider the following data: **** please view photo*** what’s wrong with the scatter plot that is suppose to represent the data

nordsb [41]

The increments are not the same, therefore the graph shows misleading data, you could fix it by changing the increments of the x variable on the x axis to 1 so it shows accurate data

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3 years ago