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Lelu [443]
3 years ago
14

What is the volume of a right circular cylinder with a base diameter of 18yd. And a height of 3yd.

Mathematics
1 answer:
saveliy_v [14]3 years ago
8 0

Answer:

Volume=254 to the nearest cubic yard.

Step-by-step explanation:

The volume of a right circular cylinder can be calculated using the formula;

Volume=\pi r^2h.

The diameter of the base is given to us. We divide it into two to obtain the radius.

r=\frac{18}{2}=9yd and also the height of the cylinder is h=3yd.

We substitute these values into the formula to obtain;

Volume=9^2\times 3\pi yd^3

Volume=243\pi yd^3

Volume=763.4yd^3

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Given that ABCD is a rhombus, find the value of x.<br> (X+14)
Kay [80]

Answer:

option B. x=38^o

Step-by-step explanation:

we know that

1) The two diagonals of a rhombus are perpendicular

2) The sum of the interior angles in any triangle must be equal to 180 degrees

Let

O ----> the intersection point of the diagonals of the rhombus

In the right triangle OAD

x^o+(x+14)^o+90^o=180^o

solve for x

x^o+(x+14)^o=90^o

2x=90^o-14^o

2x=76^o

x=38^o

6 0
3 years ago
Solve for [x]. The polygons in each<br> 2x-20<br> 16<br> 16<br> 8
Nataly_w [17]

\quad \huge \quad \quad \boxed{ \tt \:Answer }

\qquad \tt \rightarrow \:x = 16

____________________________________

\large \tt Solution  \: :

If two polygons are similar, their corresponding sides ratios will be equal to each other.

\qquad \tt \rightarrow \:  \cfrac{8}{16}  =  \cfrac{2x - 20}{24}

\qquad \tt \rightarrow \:  \cfrac{1}{2}  =  \cfrac{2x - 20}{24}

\qquad \tt \rightarrow \: 2x - 20 =  \cfrac{24}{2}

\qquad \tt \rightarrow \: 2x = 12 + 20

\qquad \tt \rightarrow \: 2x = 32

\qquad \tt \rightarrow \: x = 16

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

7 0
2 years ago
A 2-column table with 7 rows. The first column is labeled x with entries negative 3, negative 2, negative 1, 0, 1, 2, 3. The sec
DochEvi [55]

The statements that are true about the intervals of the continuous function are Options 2, 4  and 5

  • f(x) ≤ 0 over the interval [0, 2].
  • f(x) > 0 over the interval (–2, 0).
  • f(x) ≥ 0 over the interval [2, ).

<h3>What is the statement about?</h3>

Looking at the values given, the intervals which satisfies the condition are known to be:

f(x)<=0 over the interval [0,2]

f(x)>0 over the interval (-2,0)

f(x)>=0 over the interval [2,∞)

Because:

Since the table with x  and f(x) values, we have to examine analyze the table and see the each option that is in line with f(x) or not .

Examine the values of x that is from -3 to 3, the f(x) values are both positive and negative . hence f(x)>0 is false over the interval (-∞,3)

Looking at the the interval from 0 to 2, the f(x) values are 0 and negative. Hence, f(x)<=0 over the interval [0,2]

When you look over the interval (-1,1), the f(x) values are said to be both positive and negative and as such, f(x)<0 is false over the interval (-1,1)

When you look at the interval (-2,0) , the f(x)  is positive and as such, f(x)>0 over the interval (-2,0)

Looking at the interval  [2,∞), f(x) is positive and as such, f(x)>=0 over the interval [2,∞)

Therefore, Option 2, 4 and 5 are correct.

Learn more about interval from

brainly.com/question/14454639

#SPJ1

6 0
2 years ago
Giving brainliest to best answer
Sergio [31]

Answer:

One unit to the right.

Step-by-step explanation:

I entered both equations into desmos and rootx - 1 is one unit to the right.

Desmos is a great tool for graphing

6 0
3 years ago
On the first visit to the veterinarian's office, Cora's kitten weighed 550 grams. On the second visit, the kitten had gained 350
Paraphin [41]

Answer:

On first visit, weight =550 g

Weight gained on second visit= 350 g

Weight gained on third visit= 300 g

Present weight=550+350+300= 1200

Weight gained=1200-550=650

Percentage of weight increased

-------->650/550 × 100 = 118.18\%

So the kitten gained 118% weigh

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
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