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strojnjashka [21]
3 years ago
15

Help help help please please

Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
4 0

Answer:

3/20 is the answers for the question

Step-by-step explanation:

please mark me as brainlest

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1/2 (n - 4) - 3 = 3 - (2n + 3). Find the value of n.
NikAS [45]

Answer: I think the answer is n=2

Step-by-step explanation:

5 0
3 years ago
If a new data point at 12 is added to the graph , which will be true ?
Orlov [11]

Answer:

3. The mean will increase more than median, but both will increase.

Step-by-step explanation:

We have been given a dot plot. We are asked to find the true statement, if a new data point at 12 is added to our given dot plot.

Since we know that an large valued outlier affects mean more than median, so mean will increase more than median.

Let us check this using our given information. Our data set before adding 12 is:

1, 2, 2, 2, 3, 4, 4, 4, 5.

We can see that our data set has odd number (9) of data points, so median will be the value of 5th term, that is 3.

\text{Mean}=\frac{1+2+2+2+3+4+4+4+5}{9}

\text{Mean}=\frac{27}{9}=3

Therefore, mean of our data set is 3.

Upon adding a data point at 12, our new data set will be:

1, 2, 2, 2, 3, 4, 4, 4, 5, 12.

Now our data set has 10 terms, so median will be the average of 5th and 6th term.

\text{Median}=\frac{3+4}{2}

\text{Median}=\frac{7}{2}=3.5

Therefore, the median of new data set will be 3.5.

\text{Mean}=\frac{1+2+2+2+3+4+4+4+5+12}{10}

\text{Mean}=\frac{39}{10}

\text{Mean}=3.9

Therefore, mean of new data set will be 3.9.

Upon looking at our given statements we can see that 3rd statement is true as mean and median both increased after adding 12 to our data set, but mean increased more that median. Mean and median before adding 12 was 3; but after adding 12 median became 3.5, while mean became 3.9 (which is greater than mean).



3 0
3 years ago
Read 2 more answers
So my brother needs some help :D
Sati [7]

Answer:

your mixed number would be 1 and 5/18 an improper fraction would be 23/18

Step-by-step explanation:

hope it helps you! :)

3 0
3 years ago
Read 2 more answers
Diana is buying plates and cups for a party. She wants the same number of each. Plates are sold in packs of eight and cups are s
Citrus2011 [14]

Answer:

What is the least number of plates and cups she can buy?

The least number of cups of plates and cups she can buy is 24

How many packs of plates?

3 packs of plates

How many packs of cups?

2 packs of cups

Step-by-step explanation:

What is the least number of plates and cups she can buy?

We solve this using the Lowest Common Multiple method

The L.C.M of 8 and 12

Multiples of 8: 8, 16, 24, 32, 40

Multiples of 12: 12, 24, 36, 48

Therefore,

LCM(8, 12) = 24

Hence, the least number of cups and plates she can buy is 24

How many packs of plates?

Plates are sold in packs of eight

Hence: 24 ÷ 8 = 3 packs of plates

How many packs of cups?

Cups are sold in packs of 12

Hence: 24 ÷ 12 = 2 packs of cups

3 0
3 years ago
Pls Help!!! i'll mark the right answer brainliest
Soloha48 [4]

Answer:

To apply the Perpendicular Bisector Theorem, the land surveyor need to identify;

The midpoint along the line connecting the two stakes

Step-by-step explanation:

The distance between the two stakes placed by the land surveyor = 500 ft.

The distance between the third stake on the perpendicular line and the line between the two stakes = 100 ft.

The perpendicular bisector theorem states that points on the perpendicular bisector to a line are of equal length to both ends of the line to which is perpendicular to

Given that all points on a perpendicular bisector are equidistant from the two end points of the line from which it is constructed, the midpoint on the line from which the perpendicular bisector is constructed is equidistant from the end points of the line and is therefore a point on the perpendicular bisector

Therefore;

The land surveyor need to identify the midpoint along the line connecting the two stakes in order to create a perpendicular bisector from which the 100 ft. location of the third stake such that it is equidistant from the other two stakes.

4 0
3 years ago
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