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Ulleksa [173]
3 years ago
5

The daily high temperature on October 31 in a certain city is normally distributed with µ = 50 and σ = 8 . What is the probabili

ty that the high temperature on October 31 in a randomly chosen year will be between 46 degrees and 58 degrees? (Give your answer as a decimal rounded to 4 decimal places.)
Mathematics
1 answer:
tatyana61 [14]3 years ago
8 0

Answer:

0.5328

Step-by-step explanation:

µ = 50

σ = 8

We are supposed to find the probability that the high temperature on October 31 in a randomly chosen year will be between 46 degrees and 58 degrees

P(46 < x< 58)

Formula : Z=\frac{x-\mu}{\sigma}

at x = 46

Z=\frac{46-50}{8}

Z=-0.5

Refer the z table for p value

p value = 0.3085

at x = 58

Z=\frac{58-50}{8}

Z=1

Refer the z table for p value

p value = 0.8413

P(46 < x< 58)=P(x

Hence the probability that the high temperature on October 31 in a randomly chosen year will be between 46 degrees and 58 degrees is 0.5328

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