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mamaluj [8]
3 years ago
13

Point-slope of line's equation (-3,-7),(-8-11)

Mathematics
1 answer:
Nataly_w [17]3 years ago
3 0
Steps:
1. Find the slope by using the slope formula
Y2-Y1
---------
X2-X1

-11 + 7
----------
-8 + 3
2.
-11 + 7= -4
-8 + 3= -5
3. Your slope is 4/5 (because you have to turn two negatives into a positive)
4. Now you do the point-slope formula
Y-Y1= m(x-x1)
Y +7=4/5 (x +3)
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Top answer · 0 votes

So then the linear function is y = f(x) = (-1/2)X - 3 y = g(x) = 1/2 * f(x) = (-1/4)x - 3/2 y-intercept is (-1/4)(0) - 3/2 = 0 - 3/2 = -3/2 ... More

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Step-by-step explanation:

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2 years ago
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