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maw [93]
3 years ago
6

Solve:........................

x%20-%201%7D%7B5%7D%20" id="TexFormula1" title=" \frac{x}{3} + 4 = \frac{4x - 1}{5} " alt=" \frac{x}{3} + 4 = \frac{4x - 1}{5} " align="absmiddle" class="latex-formula">

​
Mathematics
1 answer:
lakkis [162]3 years ago
7 0

Answer:

\frac{x}{3}  + 4 =  \frac{4x - 1}{5}  \\  \\  \frac{x}{3}  +  \frac{12}{3}  =  \frac{4x - 1}{5}  \\  \\  \frac{x + 12}{3}  =  \frac{4x - 1}{5}  \\  \\ 3(4x - 1) = 5(x + 12) \\  \\ 12x - 3 = 5x + 60 \\  \\ 12x - 5x = 60 + 3 \\  \\ 7x = 63 \\  \\ x =  \frac{63}{7}  \\  \\ x = 9

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Answer:

1) The linear equation in point and slope form is y - 67 = -4 × (x - 14)

2) The variables are;

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3) Jennifer received 123 pieces of candies on Halloween

Step-by-step explanation:

The given parameters are;

The number of candies Jennifer eats everyday = 4 pieces

The number of days for which Jennifer eats the daily 4 candies = 14

The number of candies left at the end of the 14th day = 67 candies

1) We note that the rate of decrease in the number of candies = 4 candies/day

Therefore, the slope of the linear equation is m = -4

The y-intercept = The initial amount of candies Jennifer has = c = 67 + 14× 4 = 123 candies

The linear equation in point and slope form is given as follows;

y - 67 = -4 × (x - 14)

2) The variables are;

a) The y-value represents the number of candies available on a specific day

b) The x value represents the number of days Jennifer eats the candies'

c) The slope = The rate of decrease in the number of candies per day = -4

3) The number of candies Jennifer receives on Halloween is given by the y-intercept of the straight line equation as follows;

y - 67 = -4 × (x - 14)

y - 67 = -4·x + 56

y = -4·x + 56 + 67 = -4·x + 123

y = -4·x + 123

Comparing the above equation, with the general form of the straight line equation, y = m·x + c, where, the constant term, c = The y-intercept, we have;

The y-intercept of the equation y = -4·x + 123 = 123 = The initial amount of candies Jennifer received on Halloween.

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