I think it's d hope it helps
Answer:
The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).
Step-by-step explanation:
The (1 - <em>α</em>)% confidence interval for the difference between population means is:
The information provided is as follows:
The critical value of <em>z</em> for 98% confidence level is,
Compute the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 as follows:
Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).
First, let’s all acknowledge that whoever comes up with problems like this WANTS kids to hate math...smh
I’m sure there is a prettier way to solve this, but here’s what I did:
8(2.25) + 3(22.50) =
18 + 67.50 = 85.50 per “set” of balls/jerseys
400/85.50 = 4.678 = number of “sets” he can buy. Round down to 4 so we have room for tax.
85.5 x 4 “sets”= $342
Tax on 342 is 0.06 x 342 = 20.52
$342 + 20.52 = $362.52 spent
Basketballs = 4 sets x 8 balls per set= 32
Jerseys = 4 sets x 3 jerseys per set= 12
32 basketballs, 12 jerseys, $362.52 spent
They are going up by 2.15
1/3 x pi x radius squared
1/3 x pi x 0.7225 = 0.7566002307
0.76 to nearest hundredth