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NARA [144]
3 years ago
9

How are the shapes alike

Mathematics
1 answer:
iren [92.7K]3 years ago
7 0
1. Each shape has 6 faces
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What is the greatest common factor of 3 and 27?
Drupady [299]

Answer:

3

Step-by-step explanation:

because 3 is the only number that goes into both 3 and 27

8 0
3 years ago
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function f of x is a straight line which joins the ordered pairs negative 2.8, 16.4 and 3.5, negative 2.5. Function g of x is a
Alecsey [184]
Given the graph of the function
f(x)=-3x+8
and the graph of the function
g(x)=(0.25)^x

-3x+8=(0.25)^x when f(x) = g(x).
This occurs at the point(s) of intersection of the graphs of the function f(x) and g(x).

From the graph, we can approximate the points of intersection of the graphs of the function f(x) and g(x) to pe points (-1.9, 13.7) and (2.7, 0).
5 0
3 years ago
Find the rectangular coordinates of the point (squareroot3, pi/6)
svet-max [94.6K]

Answer:

The rectangular coordinates of the point are (3/2 , √3/2)

Step-by-step explanation:

* Lets study how to change from polar form to rectangular coordinates

- To convert from polar form (r , Ф) to rectangular coordinates (x , y)

 use these rules

# x = r cos Ф

# y = r sin Ф

* Now lets solve the problem

∵ The point in the rectangular coordinates is (√3 , π/6)

∴ r = √3 and Ф = π/6

- Lets find the x-coordinates

∵ x = r cos Ф

∵ r = √3

∵ Ф = π/6

∴ x = √3 cos π/6

∵ cos π/6 = √3/2

∴ x = √3 (√3/2) = 3/2

* The x-coordinate of the point is 3/2

- Lets find the y-coordinates

∵ y = r sin Ф

∵ r = √3

∵ Ф = π/6

∴ y = √3 sin π/6

∵ sin π/6 = 1/2

∴ y = √3 (1/2) = √3/2

* The y-coordinate of the point is √3/2

∴ The rectangular coordinates of the point are (3/2 , √3/2)

6 0
3 years ago
Which fraction is 16/40 in lowest terms
yawa3891 [41]
2/5 I believe. Correct me if I am wrong
6 0
3 years ago
Read 2 more answers
Which coefficient matrix represents a system of linear equations that has a unique solution ?
finlep [7]

Answer:

Option C

Step-by-step explanation:

We are given a coefficient matrix along and not the solution matrix

Since solution matrix is not given we cannot check for infinity solutions.

But we can check whether coefficient matrix is 0 or not

If coefficient matrix is zero, the system is inconsistent and hence no solution.

Option A)

|A|=\left[\begin{array}{ccc}4&2&6\\2&1&3\\-2&3&-4\end{array}\right] =0

since II row is a multiple of I row

Hence no solution or infinite

OPtion B

|B|=\left[\begin{array}{ccc}2&0&-2\\-7&1&5\\4&-2&0\end{array}\right] \\=2(10)-2(10)=0

Hence no solution or infinite

Option C

\left[\begin{array}{ccc}6&0&-2\\-2&0&6\\1&-2&0\end{array}\right] \\=2(36-2)=68

Hence there will be a unique solution

Option D

\left[\begin{array}{ccc}5&10&5\\4&1&4\\-1&-2&-1\end{array}\right] \\=2(10)-2(10)=0=0

(since I row is -5 times III row)

Hence there will be no or infinite solution

Option C is the correct answer



4 0
3 years ago
Read 2 more answers
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