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Solnce55 [7]
3 years ago
13

The first term of an arithmetic sequence is equal to four and the common difference is three. find the formula for the value of

the nth term
Mathematics
1 answer:
hichkok12 [17]3 years ago
7 0

The formula for the value of nth term is a_{n} = 3n + 1

Step-by-step explanation:

The formula of the nth term in the arithmetic sequence is

a_{n}=a+(n-1)d , where

  • a is the first term of the sequence
  • d is the common difference between each two consecutive terms

∵ The first term of an arithmetic sequence is equal to four

∴ a = 4

∵ The common difference is equal to three

∴ d = 3

- Substitute these values in the rule of the nth term

∵ a_{n}=a+(n-1)d

∴ a_{n}=4+(n-1)3

- Simplify it

∴ a_{n}=4+3n-3

∴ a_{n}=1+3n

The formula for the value of nth term is a_{n} = 3n + 1

Learn more:

You can learn more about the sequence in brainly.com/question/7221312

#LearnwithBrainly

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7 0
4 years ago
(0.4k3 – 2.5k) – (2.4k3 + 3k2 – 1.2k) =
Y_Kistochka [10]
Its –2k3<span> – 3k</span>2<span> – 1.3k that's what it is for sure</span>
3 0
3 years ago
Read 2 more answers
A surf shop rents surfboards and charges x dollars for one rental day. it gives a discount for a weekly seven day rental and onl
Artyom0805 [142]

A. The shop charges $8.517 for a one-day rental

B. The shop charges $42.857 for a weekly rental.

Step-by-step explanation:

Step 1; The shop charges $x for a one-day rental and $5x for a weekly rental. Assume $x = a and $5x = b, from this we can write,

5a = b, take this as equation 1.

Step 2; The shop had a total sale of $600 by renting 20 boards for a one-day rental and 10 boards for a weekly rental. So,

20a + 10b = 600, take this as equation 2.

Substituting equation 1 in 2, we get

20a + 10 (5a) = 600,

20a + 50a = 600, a = 600 / 70,

a = $8.5714.

From equation 1, 5a = b,

5 × $8.5714 = b,

b = $42.857.

So for a one-day rental, the shop charges $8.5714 and for a weekly rental it charges $42.857.

6 0
3 years ago
Hello! Help me in my question.​
erastovalidia [21]

Answer:

what is your questions?

6 0
3 years ago
Read 2 more answers
As pointed out, you lose if the pile has 1, 6, 11 or 16 sticks. How many sticks are needed in the next two piles for you to lose
muminat

Answer:

21 and 26 totaling 47sticks

Step-by-step explanation:

Th number of sticks form an arithmetic progression

1, 6, 11, 16...

The nth term of an arithmetic progression is expressed as;

Tn = a+(n-1)d

a is the first term = 1

d is the common difference

d = 6-1 = 11-6 = 5

n is the number of terms

The next two terms are the fifth and sixth term

T5 = 1+(5-1)5

T5 = 1+4(5)

T5 = 1+20

T5 = 21

T6 = 1+(6-1)5

T6 = 1+5(5)

T6 = 1+25

T6 = 26

Hence the number of sticks needed in the next two piles are 21 and 26 totaling 47sticks

4 0
3 years ago
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