How do you write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1,1)

2 answers:

8 0

The equation of a line in slope-intercept form<span> is

y = mx + b
</span><span>where m represents the </span>slope<span> and b, the y-intercept.

</span>here we have m = 2 and so the partial equation<span> is
</span>y = 2x + b

To find the value of b, substitute the coordinates of the point (1 ,1) into the partial equation<span> That is x = 1 and y = 1.
</span>

-> (2 x 1) + b = 1 -> 2 + b = 1 -> b = -1
-> y = 2x - 1 is equation in slope-intercept form

harkovskaia [24]3 years ago

7 0

First you have to put it into point-slope form before you can write it in slope-intercept form which is y-y1=m(x-x1)

Y-1=2(x-1)
Distribute the 2 to the x and -1
Y-1=2x-2
Move it all to one side
Y=2x-1

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Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

A^-1/[a^-1 - b^-1] + a^-1/[a^-1 + b^-1]

o-na [289]

$\dfrac{a^{-1}}{a^{-1}-b^{-1}}+\dfrac{a^{-1}}{a^{-1}+b^{-1}}=a^{-1}\left(\dfrac{a^{-1}+b^{-1}}{(a^{-1}-b^{-1})(a^{-1}+b^{-1})}+\dfrac{a^{-1}-b^{-1}}{(a^{-1}+b^{-1})(a^{-1}-b^{-1})}\right)$