How do you write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1,1)

2 answers:

8 0

The equation of a line in slope-intercept form is

y = mx + b
where m represents the slope and b, the y-intercept.

here we have m = 2 and so the partial equation is
y = 2x + b

To find the value of b, substitute the coordinates of the point (1 ,1) into the partial equation That is x = 1 and y = 1.


-> (2 x 1) + b = 1 -> 2 + b = 1 -> b = -1
-> y = 2x - 1 is equation in slope-intercept form

harkovskaia [24]3 years ago

7 0

First you have to put it into point-slope form before you can write it in slope-intercept form which is y-y1=m(x-x1)

Y-1=2(x-1)
Distribute the 2 to the x and -1
Y-1=2x-2
Move it all to one side
Y=2x-1

You might be interested in

A, B, and C are collinear, and B is between A and C. The ratio of AB to AC is 1:4. If A is at (-7,-8) and B is at (-3,-5) what a

Galina-37 [17]

To get the coordinates of C we shall proceed as follows:

AB:BC=1:4
B-A=[(-3--7),(-5--8)]=(4,3)
4(4,3)=(16,12)
thus the coordinates of C will be:
(16-3,-5+12)
=(13,7)

6 0

3 years ago

Read 2 more answers

Need help with a simple problem 2^x=3^x+1

KiRa [710]

For $x\ \textgreater \ 0$ , $2^x\ \textless \ 3^x$ , all the more $2^x\ \textless \ 3^x+1$ , therefore no solution.

For $x=0$ , we have $2^0=3^0+1 \Rightarrow 1=1+1 \Rightarrow 1=2$ . Obviously that' false.

For $x\ \textless \ 0$ both $2^x$ and $3^x$ , where $2^x\ \textgreater \ 3^x$ , belong to the range $(0,1)$ , then $3^x+1$ belong to the range $(1,2)$ .
Those ranges don't have a common part, therefore, again, no solution.

So, the equation $2^x=3^x+1$ doesn't have a solution.

4 0

3 years ago

PLEASE PLEASE PLEASE HELP.

ZanzabumX [31]

Answer:

Step-by-step explanation:

The quotient is the result of dividing x by 5

The expression is then

15 - $\frac{x}{5}$ → D