How do you write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1,1)
2 answers:
The equation of a line in slope-intercept form<span> is
y = mx + b
</span><span>where m represents the </span>slope<span> and b, the y-intercept.
</span>here we have m = 2 and so the partial equation<span> is
</span>y = 2x + b
To find the value of b, substitute the coordinates of the point (1 ,1) into the partial equation<span> That is x = 1 and y = 1.
</span>
-> (2 x 1) + b = 1 -> 2 + b = 1 -> b = -1
-> y = 2x - 1 is equation in slope-intercept form
First you have to put it into point-slope form before you can write it in slope-intercept form which is y-y1=m(x-x1)
Y-1=2(x-1)
Distribute the 2 to the x and -1
Y-1=2x-2
Move it all to one side
Y=2x-1
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