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tresset_1 [31]
3 years ago
10

How do you write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1,1)

Mathematics
2 answers:
Elina [12.6K]3 years ago
8 0
The equation of a line in slope-intercept form<span> is

y = mx + b
</span><span>where m represents the </span>slope<span> and b, the y-intercept.

</span>here we have m = 2 and so the partial equation<span> is
</span>y = 2x + b

To find the value of b, substitute the coordinates of the point (1 ,1) into the partial equation<span> That is x = 1 and y = 1.
</span>

-> (2 x 1) + b = 1 -> 2 + b = 1 -> b = -1
-> y = 2x - 1 is equation in slope-intercept form
harkovskaia [24]3 years ago
7 0
First you have to put it into point-slope form before you can write it in slope-intercept form which is y-y1=m(x-x1)

Y-1=2(x-1)
Distribute the 2 to the x and -1
Y-1=2x-2
Move it all to one side
Y=2x-1
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Answer:

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Step-by-step explanation:

Consider the figure below,

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We have to find distance BC,

Using trigonometric ratio,

\tan\theta=\frac{Perpendicular}{base}

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\tan\theta=\frac{AB}{BC}

\tan 11.1^{\circ} =\frac{4000}{BC}

Solving for BC, we get,

BC=\frac{4000}{\tan 11.1^{\circ} }

BC=\frac{4000}{0.196} (approx)

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Thus, the horizontal distance from the plane to the person on the runway is 20408.16 ft

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