Answer:
(24y^3x-20y^5x^2)/(-3y^5x^2)
= y^3x(24-20y^2x))/(-3y^5x^2)
=(24-20y^2x)/(-3y^2x)
=(24/(-3y^2x))-((20y^2x)/(-3y^2x))
=(-8/y^2x)-(-20/3)
=-8/y^2x + 20/3
B. The number of candies in the bags from Brand B is greater and less consistent than the number of candies in the bags from Brand A.
Answer:
72 maneiras
Step-by-step explanation:
O que acontecerá aqui é que um de cada tipo de roupa será selecionado.
Das 6 camisas, 1 será selecionada O número de maneiras pelas quais podemos fazer isso é 6C1 = 6
Das saias também, ela estará selecionando uma O número de maneiras que isso pode ser feito é 4C1 = 4
O terceiro é selecionar um par de sapatos de 3 e isso seria 3C1 = 3
assim o número de maneiras pelas quais ela pode fazer as seleções é 6 * 4 * 3 = 72 maneiras
<span>The urn contains 2 purple balls and 4 white balls. The player pay $4 for start the game and get $1.5 for every ball drawn until one purple ball is drawn. The maximal revenue would be $7.5 when 4 white balls and 1 purple balls are drawn.
If the purple ball is p and white ball is w, t</span>he possible sample space of drawings are {p, wp, wwp, wwwp, wwwwp}
<span>1. Write down the probability distribution for the player earning
The player earning </span>for each event depends on the number of balls drawn subtracted the ticket price.<span>
p= 2/6
The player earnings would be: 1*$1.5 -$4= - $2.5
wp= (4*2)/(6*5) = 4/15
</span>The player earnings would be: 2*1.5- $4= - $1
wwp= (4*3*2)/(6*5*4)= 1/5
The player earnings would be: 3*$1.5 -$4= $0.5
wwwp= (4*3*2*2)/(6*5*4*3*2)= 2/15
The player earnings would be: 4*$1.5 -$4= $2
wwwwp= (4*3*2*2*1)/(6*5*4*3*2*1) = 1/15
The player earnings would be: 5*$1.5 -$4= $3.5
2. Find its expected value
The expected value would be:
chance of event * earning
You need to combine the 5 possible outcomes from the number 1 to get the total expected value.
Total expected value= (1/3 * - 2.5)+ (4/15*-1) + (1/5*0.5) + (2/15 *2) + ( 1/15 *3.5)=
(-12.5 -4 + 1.5 + 4 + 3.5) /15= -$7.5
This game basically a rip off.
