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andrew-mc [135]
4 years ago
12

Given that s ⊥ t and r ⊥ t, what conclusion can be made?

Mathematics
1 answer:
Pie4 years ago
6 0

If s, r and t are given right lines in the same plane and with condition

s⊥t  and r⊥t we can conclude that s║r ( s and r are parallel).

Good luck!!!

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And now
shtirl [24]

Answer:

I know another one

Step-by-step explanation:

THERES HYDROIGEN AND HELIUM THEN LITHNIUM BERILIUM BPRON CARBON EVERYWHERE NITROGEN ALL THROUGH THE AIR WITH OXYGEN SO U CAN BREATHE AND FLUORINE FOR UR PRETTY TEETH

4 0
3 years ago
In the diagram below, RA is parallel to ET, and RT is 21 units long. Find the length of ST
pav-90 [236]

Answer:

ST = 12 units

Step-by-step explanation:

As RA is parallel to ET, the angle in R is equal to the angle in T, and the angle in A is equal to the angle in E, so the triangle RAS is similar to the triangle SET.

If RT is 21 units, we have that RS + ST = 21 -> RS = 21 - ST

Using a rule of three with the sides of the triangle (as they are proportional), we have:

RS / ST = AR / ET

(21 - ST) / ST = 6 / 8

4 * (21 - ST) = 3*ST

84 - 4*ST = 3*ST

7*ST = 84

ST = 12 units

5 0
4 years ago
Vectors: Find the vector from the point A=(−1,−7,3) to the point B=(3,−2,9).
devlian [24]

Answer:

\overrightarrow {AB} = (4,5,6)

1. 〈x,y,z〉=〈−1,−7,3〉+t〈−4,−5,−6〉 F

2. 〈x,y,z〉=〈−1,−7,3〉+t〈3,−2,9〉 F

3. 〈x,y,z〉=〈−1,−7,3〉+t〈4,5,6〉 T

4. 〈x,y,z〉=〈3,−2,9〉+t〈−1,−7,3〉 F

5. 〈x,y,z〉=〈3,−2,9〉+t〈4,5,6〉 F

Step-by-step explanation:

The vector AB is the vectorial difference between point A and B, that is:

\overrightarrow {AB} = \vec B - \vec A

Given that \vec A = (-1,-7,3) and \vec B = (3,-2,9), the vector AB is:

\overrightarrow {AB} = (3,-2,9)-(-1,-7,3)

\overrightarrow{AB} = (3-(-1),-2-(-7),9-3)

\overrightarrow {AB} = (4,5,6)

The vectorial equation of the line is represented by:

\langle x, y, z\rangle = \vec A + t \cdot \overrightarrow {AB}

Where t is the parametric variable, dimensionless. Given that \vec A = (-1,-7,3) and \overrightarrow {AB} = (4,5,6)

\langle x,y,z \rangle = \langle -1,-7,3 \rangle + t\cdot \langle 4,5,6 \rangle

Finally, the list of questions are now checked:

1. 〈x,y,z〉=〈−1,−7,3〉+t〈−4,−5,−6〉 F

2. 〈x,y,z〉=〈−1,−7,3〉+t〈3,−2,9〉 F

3. 〈x,y,z〉=〈−1,−7,3〉+t〈4,5,6〉 T

4. 〈x,y,z〉=〈3,−2,9〉+t〈−1,−7,3〉 F

5. 〈x,y,z〉=〈3,−2,9〉+t〈4,5,6〉 F

4 0
3 years ago
The information given represents lengths of sides of a right triangle with c the hypotenuse. Find the correct missing length to
Rus_ich [418]

rule =  {a}^{2}  +  {b}^{2}  =  {c}^{2}

{18}^{2}  +  {26}^{2}  =  {c}^{2}

324 + 676 = 1000

\sqrt{1000}  = 31.62

Answer = A) 31.62

3 0
3 years ago
A rectangular deck is 12 ft by 14 ft. When the length and width are increased by the same amount, the area becomes 288 sq. ft. B
alexdok [17]
To solve this problem you must apply the proccedure shown below:

 1. You have the following information given in the problem above:

 - The<span> rectangular deck has the following dimensions: 12 ft by 14 ft.
 - When the length and width are increased by the same amount, the area becomes 288 ft</span>².

 2. Therefore, you have:

 A=bxh

 288=(12x)(14x)
 288=168x²

 3. When you clear the x, you obtain:

 x=√288/168
 x=(2√21)/7≈1.31
 
6 0
3 years ago
Read 2 more answers
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