To solve this, you have to know that the first derivative of a function is its slope. When an interval is increasing, it has a positive slope. Thus, we are trying to solve for when the first derivative of a function is positive/negative.
f(x)=2x^3+6x^2-18x+2
f'(x)=6x^2+12x-18
f'(x)=6(x^2+2x-3)
f'(x)=6(x+3)(x-1)
So the zeroes of f'(x) are at x=1, x=-3
Because there is no multiplicity, when the function passes a zero, he y value is changing signs.
Since f'(0)=-18, intervals -3<x<1 is decreasing(because -3<0<1)
Thus, every other portion of the graph is increasing.
Therefore, you get:
Increasing: (negative infinite, -3), (1, infinite)
Decreasing:(-3,1)
Answer:
(0, 3)
Step-by-step explanation:
The y-intercept of any function can generally be defined as: 
, since the y-intercept is when the function crosses the y-axis.
Anywhere on the y-axis, the x-value = 0, so the x value of the y-intercept will always be 0, and the y value is f(0), since x=0.
By looking at the graph it appears to intercept the y-axis at (0, 3) which should be the answer
A.) 0.55
This is because the probability has to com out to 1 (technically 100%) so, 1-0.45 is 0.55 (these could all be percentages if you multiply them by 100)
Answer:
x= 15/16
Step-by-step explanation:
