A three-phase, 60 Hz, synchronous wound rotor machine acting as generator is observed to have a terminal voltage of 460 Vrms and
a magintude terminal current of 140 Arms at a power factor of 0.88 lagging. The field current under this operation is 50 A. The synchronous reactance is 1.0 and you can assume the armature resistance to be negligible. Analytically find:
(a) 10pts. The internal voltage of the machine
(b) 10pts. The magnitude of the field-to-armature mutual inductance.
(c) 10pts. The electrical power output in both kW and HP.
(d) 5pts. Draw the phasor diagram of the internal voltage, the machine line voltage drop, and the terminal voltage of the machine.
(e) 5pts. What is the electrical phase angle difference value between the magnetic axis of Or and Ff?
(a) 10pts. The internal voltage of the machine
(b) 10pts. The magnitude of the field-to-armature mutual inductance.
(c) 10pts. The electrical power output in both kW and HP.
(d) 5pts. Draw the phasor diagram of the internal voltage, the machine line voltage drop, and the terminal voltage of the machine.
(e) 5pts. What is the electrical phase angle difference value between the magnetic axis of Or and Ff?
1 answer:
You might be interested in
Answer:
B. fund the project
D. are partners with a vested interest
Explanation:
If you look at the definition of the word stakeholder, these options match the definition which is why I chose B and D
Answer:
A.) 1mv = 2000N
B.) Impulse = 60Ns
C.) Acceleration = 66.67 m/s^2
Velocity = 4 m/s
Displacement = 0.075 metre
Absorbed energy = 60 J
Explanation:
A.) Using a mathematical linear equation,
Y = MX + C
Where M = (2000 - 0)/( 898 - 0 )
M = 2000/898
M = 2.23
Let Y = 2000 and X = 898
2000 = 2.23(898) + C
2000 = 2000 + C
C = 0
We can therefore conclude that
1 mV = 2000N
B.) Impulse is the product of force and time.
Also, impulse = momentum
Given that
Mass M = 30kg
Velocity V = 2 m/s
Impulse = M × V = momentum
Impulse = 30 × 2 = 60 Ns
C.) Force = mass × acceleration
F = ma
Substitute force and mass into the formula
2000 = 30a
Make a the subject of formula
a = 2000/30
acceleration a = 66.67 m/s^2
Since impulse = 60 Ns
From Newton 2nd law,
Force = rate of change in momentum
Where
change in momentum = -MV - (- MU)
Impulse = -MV + MU
Where U = initial velocity
60 = -60 + MU
30U = 120
U = 120/30
U = 4 m/s
Force = 2000N
Impulse = Ft
Substitute force and impulse to get time
60 = 2000t
t = 60/2000
t = 0.03 second
Using third equation of motion
V^2 = U^2 + 2as
Where S = displacement
4^2 = 2^2 + 2 × 66.67S
16 = 4 + 133.4S
133.4S = 10
S = 10/133.4
S = 0.075 metre
D.) Energy = 1/2 mV^2
Energy = 0.5 × 30 × 2^2
Energy = 15 × 4 = 60J
