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Scorpion4ik [409]
4 years ago
8

A three-phase, 60 Hz, synchronous wound rotor machine acting as generator is observed to have a terminal voltage of 460 Vrms and

a magintude terminal current of 140 Arms at a power factor of 0.88 lagging. The field current under this operation is 50 A. The synchronous reactance is 1.0 and you can assume the armature resistance to be negligible. Analytically find:
(a) 10pts. The internal voltage of the machine
(b) 10pts. The magnitude of the field-to-armature mutual inductance.
(c) 10pts. The electrical power output in both kW and HP.
(d) 5pts. Draw the phasor diagram of the internal voltage, the machine line voltage drop, and the terminal voltage of the machine.
(e) 5pts. What is the electrical phase angle difference value between the magnetic axis of Or and Ff?

Engineering
1 answer:
Art [367]4 years ago
4 0

Answer:

In the attached solution, the following calculations have already been calculated: Per phase , Maximum , RMS value of Internal Voltage in this sequence.

Explanation:

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A cylinder 8 in. in diameter and 3 ft long is concentric with a pipe of 8.25 in internal diameter. Between the cylinder and the
yarga [219]

Answer:

What force is requiere to move the cylinder along

Explanation:

The kinematic viscosity of the ol is 0.006 fr2

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3 years ago
What do auto mechanics do when they take out the spark plugs
ivanzaharov [21]
Check them to see if the cylinder is running rich or lean. This can be determined by looking at the electrodes on the plugs
Hope this helps.
7 0
3 years ago
A receptacle, plug, or any other electrical device whose design limits the ability of an electrician to come in contact with any
o-na [289]

Answer:

Recessed  safe

Explanation:

A recessed, receptacle or plug is one in which the metal interfacing parts have been retracted back in such a way that common contact between a person handling the receptacle or outlet will not ordinarily lead to exposure to electric shock hazard and as such improving the safety of use of such plug, receptacle or electrical device either at home or in industrial setting

A recessed outlet is also more ideal than standard outlets where there are hazards such as potential contact with water.

4 0
3 years ago
You must create a Low Pass Filter for an audio amplifier. You must pass 10khz and block
Katena32 [7]

Answer:

) You must create a Low Pass Filter for an audio amplifier. You must pass 10khz and block

60khz. In designing this, you must choose a cutoff frequency exactly half way between

these two frequencies. In addition, you must use a 0.2uF capacitor in you LPF circuit.

Given these criteria, analyze this circuit, and determine the necessary resistor value in

Ohms. Find the output Voltage at both ends of the spectrum. Based on your results, is

this a good design? NOTE: You MUST show your work (when using MS Word, choose

“Insert”--- “Equation”). (6 marks)

a. Solve for fc

b. Solve for R

c. Solve for Vout at 10khz

d. Solve for Vout at 60khz

e. Good design> (yes or no with an explanation)

Explanation:

6 0
3 years ago
A group of students launches a model rocket in the vertical direction. Based on tracking data, they determine that the altitude
Fofino [41]

Answer:

u = 260.22m/s

S_{max} = 1141.07ft

Explanation:

Given

S_0 = 89.6ft --- Initial altitude

S_{16.5} = 0ft -- Altitude after 16.5 seconds

a = -g = -32.2ft/s^2 --- Acceleration (It is negative because it is an upward movement i.e. against gravity)

Solving (a): Final Speed of the rocket

To do this, we make use of:

S = ut + \frac{1}{2}at^2

The final altitude after 16.5 seconds is represented as:

S_{16.5} = S_0 + ut + \frac{1}{2}at^2

Substitute the following values:

S_0 = 89.6ft       S_{16.5} = 0ft     a = -g = -32.2ft/s^2    and t = 16.5

So, we have:

0 = 89.6 + u * 16.5 - \frac{1}{2} * 32.2 * 16.5^2

0 = 89.6 + u * 16.5 - \frac{1}{2} * 8766.45

0 = 89.6 + 16.5u-  4383.225

Collect Like Terms

16.5u = -89.6 +4383.225

16.5u = 4293.625

Make u the subject

u = \frac{4293.625}{16.5}

u = 260.21969697

u = 260.22m/s

Solving (b): The maximum height attained

First, we calculate the time taken to attain the maximum height.

Using:

v=u  + at

At the maximum height:

v =0 --- The final velocity

u = 260.22m/s

a = -g = -32.2ft/s^2

So, we have:

0 = 260.22 - 32.2t

Collect Like Terms

32.2t = 260.22

Make t the subject

t = \frac{260.22}{ 32.2}

t = 8.08s

The maximum height is then calculated as:

S_{max} = S_0 + ut + \frac{1}{2}at^2

This gives:

S_{max} = 89.6 + 260.22 * 8.08 - \frac{1}{2} * 32.2 * 8.08^2

S_{max} = 89.6 + 260.22 * 8.08 - \frac{1}{2} * 2102.22

S_{max} = 89.6 + 260.22 * 8.08 - 1051.11

S_{max} = 1141.0676

S_{max} = 1141.07ft

Hence, the maximum height is 1141.07ft

8 0
3 years ago
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