1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
garri49 [273]
3 years ago
14

A receptacle, plug, or any other electrical device whose design limits the ability of an electrician to come in contact with any

of its electrical connections is identified as _______ safe.
a. feel

b. resessed

c. touch

d. removal
Engineering
1 answer:
o-na [289]3 years ago
4 0

Answer:

Recessed  safe

Explanation:

A recessed, receptacle or plug is one in which the metal interfacing parts have been retracted back in such a way that common contact between a person handling the receptacle or outlet will not ordinarily lead to exposure to electric shock hazard and as such improving the safety of use of such plug, receptacle or electrical device either at home or in industrial setting

A recessed outlet is also more ideal than standard outlets where there are hazards such as potential contact with water.

You might be interested in
You don't have to notify employees that a lockout/tagout is about to begin?
Sergeu [11.5K]

Answer:

When the imposter is sus : O

Explanation:

3 0
3 years ago
A six-lane freeway (three lanes in each direction) in rolling terrain has 10-ft lanes and obstructions 5 ft from the right edge.
Anon25 [30]
That is too hard but u got that cuz i believe in you!!!
3 0
3 years ago
A steel pipe of 400-mm outer diameter is fabricated from 10-mm-thick plate by welding along a helix that forms an angle of 20° w
Verdich [7]

Explanation:

Outer di ameter d_{0}=400 \mathrm{mm}[tex] Thickness of the cylinder [tex]t=10 \mathrm{mm}

\therefore[tex] Inner diam eter [tex]d_{i}=d_{0}-2 t=400-2 \times 10

d_{1}=380 \mathrm{mm}

Given loading on the cylinder P=300 \mathrm{kN} Helix an gle of the weld form \theta=20^{\circ}

(i) Normal stress on the plane at angle \theta=20^{\circ} is

\sigma=\frac{P \cos ^{2} \theta}{A_{0}}

\text { Where } A_{0}=\frac{\pi}{4}\left(d_{0}^{2}-d_{1}^{2}\right)

\quad=\frac{\pi}{4}\left(400^{2}-380^{2}\right)

=12252.21 \mathrm{mm}^{2}

=12.25221 \times 10^{-9} \mathrm{m}^{2}

\sigma=\frac{-300 \times 10^{2} \times \cos ^{2} 20}{12.25221 \times 10^{-1}}

=-21.6 \mathrm{MPa}

(ii) Shear stress along an angle of \theta=20^{\circ} is \tau=\frac{P}{A_{0}} \cos \theta \sin \theta

=\frac{-300 \times 10^{-1} \times \cos 20 \times \sin 20}{12.25221 \times 10^{-3}}

=-7.86 \mathrm{MPa}

3 0
3 years ago
A plate (A-C) is connected to steelflat bars by pinsat A and B. Member A-E consists of two 6mm by 25mm parallel flat bars. At C,
juin [17]

Answer:

stress_ac = 5.333 MPa

shear stress_c = 1.763 MPa

Explanation:

Given:

- The missing figure is in the attachment.

- The dimensions of member AC = ( 6 x 25 ) mm x 2

- The diameter of the pin d = 19 mm

- Load at point A is P = 2 kN

Find:

-  Find the axial stress in AE and the shear stress in pin C.

Solution:

- The stress in member AE can be calculated using component of force P along the member AE  as follows:

                                    stress_ac = P*cos(Q) / A_ae

Where, Angle Q: A_E_B   and A_ac: cross sectional area of member AE.

                                    cos(Q) = 4 / 5   ..... From figure ( trigonometry )

                                    A_ae = 0.006*0.025*2 = 3*10^-4 m^2

Hence,

                                    stress_ae = 2*(4/5) / 3*10^-4

                                    stress_ae = 5.333 MPa

- The force at pin C can be evaluated by taking moments about C equal zero:

                                   (M)_c = P*6 - F_eb*3

                                      0 = P*6 - F_eb*3

                                      F_eb = 0.5*P

- Sum of horizontal forces for member AC is zero:

                                      P - F_eb - F_c = 0

                                      F_c = 0.5*P

- The shear stress of double shear bolt is given by an expression:

                                     shear stress = shear force / 2*A_pin

Where, The area of the pin C is:

                                     A_pin = pi*d^2 / 4

                                     A_pin = pi*0.019^2 / 4 = 2.8353*10^-4 m^2

Hence,

                                     shear stress = 0.5*P / 2*A_pin

                                     shear stress = 0.5*2 / 2*2.8353*10^-4

                                    shear stress = 1.763 MPa

7 0
3 years ago
A copper-constantan thermocouple is to be used to measure temperatures between 0 and 200°C. The e.m.f. at 0°C is 0 mV, at 100°C
Helga [31]

Answer:

3.941%

Explanation:

5 0
3 years ago
Other questions:
  • Describe the meaning of the different symbols and abbreviations found on the drawings/documents that they use (such as BS8888, s
    12·1 answer
  • A steam power plant operates on an ideal reheat- regenerative Rankine cycle and has a net power output of 80 MW. Steam enters th
    10·1 answer
  • Yield and tensile strengths and modulus of elasticity . with increasing temperature. (increase/decrease/independent)
    11·1 answer
  • is sampled at a rate of to produce the sampled vector and then quantized. Assume, as usual, the minimum voltage of the dynamic r
    9·1 answer
  • 1. Asphyxiation is a hazard posed by Compressed Natural Gas (CNG) vehicles and can be detected when you notice
    7·1 answer
  • A(n) ____ is an exact representation of an object projected onto a plane from a specific position.
    14·1 answer
  • Which of the following is not a function of the suspension system?_____
    6·1 answer
  • If the load parameters are: Vln=600kV, Il=100A (resistive), calculate the source voltage and current when the line is 50Miles (s
    14·1 answer
  • By adding "-once", one can form the noun form of the word "organize" is that true or false?​
    5·2 answers
  • What are the horizontal structures beneath a slab that help transfer the load from the slab to the columns?
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!