Answer:
V₂ = 22.84 L
Explanation:
Given data:
Initial volume = 20.0 L
Initial pressure = 1.50 atm
Initial temperature = 23 °C (23 +273 = 296 K)
Final temperature = 271°C (271+273 = 544 K)
Final pressure = 3.50 atm
Final volume = ?
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 1.50 atm × 29.0L ×544 K / 296 K × 3.50 atm
V₂ = 23664 atm .L. K / 1036 atm.K
V₂ = 22.84 L
Answer: 2205 lb/m^3
Explanation:
- 1g = 0.002205lb
- 1cm^3 = 1x10^-6m^3
Convert: (1g/cm^3)*(0.002205lb/g)*(1cm^3/1x10^-6m^3) = 2205 lb/m^3
Answer:
A reduction potential measures the tendency of a molecule to be reduced by taking up new electrons. ... Standard reduction potentials can be useful in determining the directionality of a reaction. The reduction potential of a given species can be considered to be the negative of the oxidation potential.
Explanation:
Answer:
subsystems.
Explanation:
A self-contained system within a larger system. system. A group of interacting or interdependent elements forming a complex whole, as in all the factors or variables in an environment or all the variables that might affect a science experiment.
