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diamong [38]
3 years ago
6

If a shell can hold a maximum of 32 electrons, what is the value of n?

Chemistry
2 answers:
Anastaziya [24]3 years ago
8 0
The value for N will be 4
sweet [91]3 years ago
4 0

Answer:

The value of N would be 4.

Explanation:

The equation would be 2n^x = 32 and therefore, 4.

You might be interested in
How do the isotopes carbon-13 and carbon-14 differ?"
andreyandreev [35.5K]

Answer:

Carbon exists in several isotopes. ... Carbon-12 has 6 neutrons, carbon-13 has 7 neutrons, and carbon-14 contains 8 neutrons. Carbon-12 and 13 are stable isotopes, which means that the nucleus does not undergo radioactive decay. Carbon-14 possesses an unstable nucleus which undergoes radioactive decay.

Explanation: Trust me :)

8 0
3 years ago
The concept of determining which reactant is limiting and which is in excess is akin to determining the number of sandwiches tha
OLga [1]

Answer:

Cheese will be limiting reactant.

Explanation:

In given question it is stated that two slices of breads are required for one sandwich. The total bread slices available are 52. we divide the 52 by 2 to determine the number of sandwich which could made from 52 slices.

52/2 = 26

26 sandwich could be made from 52 bread slices.

The amount of cheese required for one sandwich is 3 slices. The available slices of cheese are 69.

69/3 =  23

we can see that only 23 set of slices of cheese are available while bread slices are available for 26 sandwiches. so we can make only 23 sandwiches from given quantity of ingredients. The 6 slices or 3 set of bread will left, because cheese is limited.

4 0
3 years ago
The cell potential for an electrochemical cell with a Zn, Zn2 half-cell and an Al, Al3 half-cell is _____ V. Enter your answer t
kap26 [50]

Answer:

0.900 V

Explanation:

Oxidation half cell;

2Al(s) -----> 2Al^3+(aq) + 6e

Reduction half equation;

3Zn^2+(aq) + 6e ----> 3Zn(s)

E°anode = -1.66V

E°cathode= -0.76 V

E°cell= E°cathode - E°anode

E°cell= -0.76-(-1.66)

E°cell= 0.900 V

3 0
4 years ago
Dinitrogen pentoxide is used in the preparation of explosives. If 7.93 mol of
Tpy6a [65]

The volume of O₂ produced: 84.6 L

<h3>Further explanation</h3>

Given

7.93 mol of  dinitrogen pentoxide

T = 48 + 273 = 321 K

P = 125 kPa = 1,23365 atm

Required

Volume of O₂

Solution

Decomposition reaction of dinitrogen pentoxide

2N₂O₅(g)→4NO₂(g)+O₂ (g)

From the equation, mol ratio N₂O₅ : O₂ = 2 : 1, so mol O₂ :

= 0.5 x mol N₂O₅

= 0.5 x 7.93

= 3.965 moles

The volume of O₂ :

\tt V=\dfrac{nRT}{P}\\\\V=\dfrac{3.965\times 0.082\times 321}{1.23365}\\\\V=84.6~L

5 0
4 years ago
Hope me with all this slide :( TYSMMM
White raven [17]

Answer:

exemples of elements with 1 valence electron: Hydrogen, lithium, potassium.

exemples of elements with 2 valence electrons: magnessium, calcium.

boron has 3 valence electrons. Phosphorus has 5 valence electrons.

carbon has 4 valence electrons.

exemples of elements with 5 valence electrons: Phosphorus, nitrogen

exemples of elements with 7 valence electrons: fluorine, chlorine

exemples of elements with 8 valence electrons: helium, argon

Explanation:

the easiest way to know the number of electrons are by the number of the group so 14 is 4, 16 is 6.

7 0
4 years ago
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