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lions [1.4K]
3 years ago
15

A teaspoon of dry coffee crystals dissolves when mixed in a cup of hot water, this process produces a solution. the original cry

stals are classified as a
A. solute
B. solvent
C. solution
D. product
Chemistry
1 answer:
Crazy boy [7]3 years ago
6 0

Answer:

A. Solute

Explanation:

The solute is the material being dissolved.

Hope it helps! :)

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Hydrogen is 99% 1H, 0.8% 2H, and 0.2% 3H. Calculate its average atomic mass.
AlekseyPX

The average atomic mass of hydrogen (99% H-1, 0.8% H-2, and 0.2% H-3) is 1.012 amu.    

The average atomic mass of hydrogen can be calculated with the following equation:

A = m_{H-1}\%_{H-1} + m_{H-2}\%_{H-2} + m_{H-3}\%_{H-3}

Where:

m_{H-1}: is the mass of protium (H-1) = 1

m_{H-2}: is the <em>mass</em> of deuterium (H-2) = 2

m_{H-3}: is the <em>mass </em>of tritium (H-3) = 3

\%_{H-1}: is the abundance percent of H-1 = 99%

\%_{H-2}: is the <em>abundance percent</em> of H-2 = 0.8%

\%_{H-3}: is the <em>abundance percent</em> of H-3 = 0.2%

The average atomic mass is:

A = 1*99\% + 2*0.8\% + 3*0.2\%

Changing all the <u>percent values</u> into <u>decimal ones</u>, we have:

A = 0.99 + 2*0.008 + 3*0.002 = 1.012

Therefore, the average atomic mass of hydrogen is 1.012 amu.

Learn more about average atomic mass here brainly.com/question/8575403?referrer=searchResults

I hope it helps you!

6 0
2 years ago
How can a measurment be both precise and accurate?
guapka [62]
Accuracy refers to the closeness of a value to a known or standard value, while precision refers to the closeness of measurements (two or more) to each other. 

The best way to remember how to distinguish between the two definitions and apply them is to think of archery. The archer's goal is to be both accurate and precise. To do this, he/she must try and shoot each arrow as close to the middle and as close to each other as possible. If the archer's arrows landed all over the target, these shots would be neither accurate nor precise. If the arrows landed closely to each other, but far away from the middle, these shots would be considered precise, but not accurate. If the arrows all landed closely to each other AND in the middle, the shots would be BOTH accurate and precise.

So, if you consistently measured values that were close to each other, and were close to the accepted/known value, then your measurements would be both accurate and precise. 


I hope this helps you.
5 0
3 years ago
How much heat is needed to vaporize 10.00 grams of water at 100.0°c? the latent heat of vaporization of water is 2,259 j/g. 22.5
puteri [66]

The correct option is:

The latent heat of vaporization of water is given by option D. 22,590J

Latent heat of vaporization:

Latent heat of vaporization is energy required to change 1 kg of liquid to gas at atmospheric pressure at its boiling point.

Also, Latent heat is the energy released or absorbed during a phase change.

Energy released during phase change is Exothermic process.

Whereas energy absorbed during phase change is Endothermic process.

Q=mL

Q= Latent heat

m= mass= 10 g

L= Latent heat of vaporization= 2,259 J/g

Putting the values in the above equation:

Q=10*2259

Q=22590 L

Learn more about 1st law of thermodynamics here,

brainly.com/question/20114432

#SPJ4

8 0
2 years ago
What is safe storage of produced materials​
Liono4ka [1.6K]

Answer:

Stacking bags and bundles.

Explanation:

Interlock them in rows to ensure they're secure.

6 0
2 years ago
Read 2 more answers
A student calculated the density of a sample of graphite to be 2.3 g/cm3. Show a numerical setup for calculating the student’s p
LUCKY_DIMON [66]

Answer:

Percent error = 1.5%

Explanation:

Given data:

Measured value of density of graphite = 2.3 g/cm³

Percent error = ?

Solution:

Formula:

Percent error = [Measured value - Actual value / actual value] × 100

Actual/accepted value of density of graphite = 2.266 g/cm³

Now we will put the values:

Percent error = [2.3 g/cm³ - 2.266 g/cm³ / 2.266 g/cm³] × 100

Percent error = [0.034 g/cm³ / 2.266 g/cm³] × 100

Percent error = 0.015  × 100

Percent error = 1.5%

8 0
2 years ago
Read 2 more answers
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