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SVEN [57.7K]
3 years ago
13

Find the point-slope equation for the line that passes through the points (30,2) and (15,-28) use the first point in your equati

on
Mathematics
1 answer:
Sladkaya [172]3 years ago
4 0

Answer:

y=2x-58

Explanation:

In order to write our point-slope formula (y=mx+C format), we first need to figure out the slope (m). To figure out the slope, we divide the change in y by the change in x between the two points (rise/run). The rise is 30 (2-(-28)) and the run is 15 (30-15). Therefore the slope is 2 (30/15)

This gives us:

y=2x + c

Now to figure out C (which will be the y-intercept of the graph) we substitute in the values from one of the points. So our x=30 and our y=2:

2=2(30) + c

2=60+c

2-60=c

-58=c

So now we know that our C (constant) is - 58.

Hence our point-slope formula is:

y=2x-58

Which you can test with the other point:

-28=2(15) - 58

Hope this helped!

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Answer:

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Step-by-step explanation:

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Multiply through by 8 to clear the fractions

6(x - 3) - 40 = x - 1 ← distribute parenthesis and simplify left side

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3 0
3 years ago
Is it possible to form a triangle with the given side lengths? 15 yd,16yd,30yd
lukranit [14]

<u>Answer:</u>

<h2>Yes</h2>

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Let h(x)=2x−5 and g(x)=−3x+1.Find h(x)+g(x).? help please
Aleksandr-060686 [28]
This may look a little confusing but all you have to do is plug the equation given for h(x) which is 2x-5 in to the h(x) area in the equation where it says h(x) + g(x).

So far that’s (2x-5) + g(x)

Then,

Do the same with equation given for g(x) which is now,

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