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Tanzania [10]
2 years ago
11

If 2000 is placed into a bank account that pays 3% compound interest per year how much will be in the account after 2 years

Mathematics
1 answer:
Margarita [4]2 years ago
5 0

Answer:

Account Balance = Principal x (1 + interest rate (decimal)) number of years, compounded annually.

Step-by-step explanation:

This is based on the information provided: 2121.80 (1.03)2 = 2000 So, on your initial deposit of 2000, you can collect 121.80 in interest after two years.

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Karen has 7 over 8cup of ice cream. How many 1 over 3cup servings can she make?
STALIN [3.7K]

Answer:

<em>1 and 5 over 24</em>

Step-by-step explanation:

its right trust me because 1+1 is 3

8 0
2 years ago
How should this problem be solved?(a3)2
baherus [9]
You can not "solve" this, so to speak, rather simplify this expression. Take the "2" and multiply that by the "a" and the "3" in the parentheses. You will then have the simplified answer of: 2a times 6. 
Hope that helps!
8 0
3 years ago
If A's income is 25% less than that of B, then how much percent is B's income more than that of A?​
saul85 [17]
Let's say that B makes $100.

Then A makes $75.

So, your question then becomes 100 is what percent of 75?

This can be solved by setting up the proportion 100 / 75 = x / 100

75x = 10000

x = 133.3

So, B's income is 33.3% more than A's income.
7 0
3 years ago
Find the area under the standard normal probability distribution between the following pairs of​ z-scores. a. z=0 and z=3.00 e.
prohojiy [21]

Answer:

a. P(0 < z < 3.00) =  0.4987

b. P(0 < z < 1.00) =  0.3414

c. P(0 < z < 2.00) = 0.4773

d. P(0 < z < 0.79) = 0.2852

e. P(-3.00 < z < 0) = 0.4987

f. P(-1.00 < z < 0) = 0.3414

g. P(-1.58 < z < 0) = 0.4429

h. P(-0.79 < z < 0) = 0.2852

Step-by-step explanation:

Find the area under the standard normal probability distribution between the following pairs of​ z-scores.

a. z=0 and z=3.00

From the standard normal distribution tables,

P(Z< 0) = 0.5  and P (Z< 3.00) = 0.9987

Thus;

P(0 < z < 3.00) = 0.9987 - 0.5

P(0 < z < 3.00) =  0.4987

b. b. z=0 and z=1.00

From the standard normal distribution tables,

P(Z< 0) = 0.5  and P (Z< 1.00) = 0.8414

Thus;

P(0 < z < 1.00) = 0.8414 - 0.5

P(0 < z < 1.00) =  0.3414

c. z=0 and z=2.00

From the standard normal distribution tables,

P(Z< 0) = 0.5  and P (Z< 2.00) = 0.9773

Thus;

P(0 < z < 2.00) = 0.9773 - 0.5

P(0 < z < 2.00) = 0.4773

d.  z=0 and z=0.79

From the standard normal distribution tables,

P(Z< 0) = 0.5  and P (Z< 0.79) = 0.7852

Thus;

P(0 < z < 0.79) = 0.7852- 0.5

P(0 < z < 0.79) = 0.2852

e. z=−3.00 and z=0

From the standard normal distribution tables,

P(Z< -3.00) = 0.0014  and P(Z< 0) = 0.5

Thus;

P(-3.00 < z < 0 ) = 0.5 - 0.0013

P(-3.00 < z < 0) = 0.4987

f. z=−1.00 and z=0

From the standard normal distribution tables,

P(Z< -1.00) = 0.1587  and P(Z< 0) = 0.5

Thus;

P(-1.00 < z < 0 ) = 0.5 -  0.1586

P(-1.00 < z < 0) = 0.3414

g. z=−1.58 and z=0

From the standard normal distribution tables,

P(Z< -1.58) = 0.0571  and P(Z< 0) = 0.5

Thus;

P(-1.58 < z < 0 ) = 0.5 -  0.0571

P(-1.58 < z < 0) = 0.4429

h. z=−0.79 and z=0

From the standard normal distribution tables,

P(Z< -0.79) = 0.2148  and P(Z< 0) = 0.5

Thus;

P(-0.79 < z < 0 ) = 0.5 -  0.2148

P(-0.79 < z < 0) = 0.2852

8 0
3 years ago
What percent of 12.4 is 12.4
NARA [144]
To find a percentage divide the first number by the second.

\frac{12.4}{12.4}=\frac{1}{1}=1.00

Now that you have your number, move the decimal point over 2 to the right and add your percentage sign.

100.00%

Your answer is 100%
3 0
3 years ago
Read 2 more answers
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