What’s 25.41 divided by 33? I need to see work because I don’t get it

Miss Stevens drove through a total of 36 intersections on her way home from work last week at four of every 16 intersections Mis

Nostrana [21]

Answer:

8 intersections

Step-by-step explanation:

Miss Stevens drove through a total of 36 intersections on her way home from work last week.

At four of every 16 intersections Miss Stevens had to stop for a red light before she could drive through .

This is calculated as:

36 intersections ÷ 16 intersections

= 2 4/16

= 2 1/4

At four of every 16 intersections Miss Stevens had to stop for a red light before she could drive through .

4 of every 16 intersections = stop for a red light

Hence:

16/4 = 4 intersections

Hence: 4 intersections = 1 stop for a read

The number of intersections that Miss Stevens had to stop for a red light is:

2 × 4 intersections = 8 intersections

6 0

2 years ago

Pls help me with this question I’m trying to Anwser

tino4ka555 [31]

Answer:Wish i could help, but I'm just as confused.

Step-by-step explanation:

8 0

3 years ago

What are the solutions of the equation 9x4 – 2x2 – 7 = 0? Use u substitution to solve. tions of the equation 9

skelet666 [1.2K]

Answer:

Step-by-step explanation:

Let $u^2=x^4\\u = x^2$

Subbing in:

$9u^2-2u-7=0$

a = 9, b = -2, c = -7

The product of a and c is the aboslute value of -63, so a*c = 63. We need 2 factors of 63 that will add to give us -2. The factors of 63 are {1, 63}, (3, 21}, {7, 9}. It looks like the combination of -9 and +7 will work because -9 + 7 = -2. Plug in accordingly:

$9u^2-9u+7u-7=0$

Group together in groups of 2:

$(9u^2-9u)+(7u-7)=0$

Now factor out what's common within each set of parenthesis:

$9u(u-1)+7(u-1)=0$

We know this combination "works" because the terms inside the parenthesis are identical. We can now factor those out and what's left goes together in another set of parenthesis:

$(u-1)(9u+7)=0$

Remember that $u=x^2$

so we sub back in and continue to factor. This was originally a fourth degree polynomial; that means we have 4 solutions.

$(x^2-1)(9x^2+7)=0$

The first two solutions are found withing the first set of parenthesis and the second two are found in other set of parenthesis. Factoring $(x^2-1)$ gives us that x = 1 and -1. The other set is a bit more tricky. If