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3 years ago

7

Using the following to answer the question: p: 3 is an even number q: 9 is an even number Using a truth table, determine whether

the following conjunction is true or false: p ^ q

1 answer:

kogti [31]3 years ago

8 0

false.............................

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Triangle abc is similar to triangle FGH solve for p plebs.

12345 [234]

The value of <em>p </em>is 21

Step-by-step explanation:

ΔABC ~ ΔFGH

$\frac{ab}{fg} = \frac{bc}{gh} \\ \frac{35}{p} = \frac{10}{6} \\ p = \frac{35 \times 6}{10} \\ p = \frac{210}{10} \\ p = 21 \\ \\ or \\ \\ \frac{ab}{fg} = \frac{ac}{fh} \\ \frac{35}{p} = \frac{30}{18} \\ p = \frac{35 \times 18}{30} \\ p = \frac{630}{30} \\ p = 21$

So, the value of <em>p</em> is 21

<em>Hope </em><em>it </em><em>helpful </em><em>and </em><em>useful </em><em>:</em><em>)</em>

5 0

3 years ago

Jeff uses the expression 2(3b + 1) to determine how many books (b) he needs to order for his store. If b = 12, how many books sh

kari74 [83]

Answer:

73

Step-by-step explanation:

you write 12 instead of b

4 0

3 years ago

Read 2 more answers

The graph of the function B is shown below. If B(x) = -1, then what is x?

Salsk061 [2.6K]

Answer:

there isnt enough info

Step-by-step explanation:

5 0

3 years ago

A rectangular garden measures 40 yards by 35 yards. a lawn of uniform width surrounds the garden and has an area of 316 square y

timofeeve [1]

The lawn area of uniform width can be written as follows:
A = (40 + 2x) * (35 + 2x) - (40) * (35)
Where,
x: width of the lawn
Substituting the value of the area we have:
316 = (40 + 2x) * (35 + 2x) - (40) * (35)
Rewriting:
316 = 1400 + 80x + 70x + 4x ^ 2 - 1400
Rewriting we have:
4x ^ 2 + 150x - 316 = 0
Solving the polynomial we have:
x1 = - 79/2
x2 = 2
Taking the positive root we have that the grass width des:
x = 2 yards
Answer:
The width of the lawn that surrounds the garden is:
x = 2 yards

5 0

3 years ago

1. Bob tried to answer the following question by finding the missing angle and rounding the answer to the nearest degree.

iren2701 [21]

Answer:

Part 1)

Bob's mistake was to have used the cosine instead of the sine

The measure of the missing angle is $53.13\°$

Part 2) The surface area of the pyramid is $288\ cm^{2}$

Step-by-step explanation:

Part 1)

Let

x----> the missing angle

we know that

In the right triangle o the figure

The sine of angle x is equal to divide the opposite side angle x to the hypotenuse of the right triangle

$sin(x)=\frac{16}{20}$

$x=arcsin(\frac{16}{20})=53.13\°$

Bob's mistake was to have used the cosine instead of the sine

Part 2) we know that

The surface area of the square pyramid is equal to the area of the square base plus the area of its four lateral triangular faces

so

$SA=b^{2}+4[\frac{1}{2}(b)(h)]$

where

b is the length side of the square

h is the height of the triangular lateral face

In this problem

$h=b/2$ -------> by an 45° angle

so

$b=2h$

$sin(45\°)=\frac{h}{6\sqrt{2}}$

$h=6\sqrt{2}(sin(45\°))=6\ cm$

Find the value of b

$b=2(6)=12\ cm$

Find the surface area

$SA=12^{2}+4[\frac{1}{2}(12)(6)]=288\ cm^{2}$

3 0

4 years ago