Compare and contrast the polyp and medusa stages of a typical jellyfish.

what inputs do plants need to carry out photosynthesis and how might you provide these on another planet

Fittoniya [83]

The inputs all plants need to carry out photosynthesis are water(H2O) + carbon dioxide (CO2) + sunlight

7 0

3 years ago

Place all eight of these steps of the insulin signaling pathway in the correct order. The abbreviation PIP 2 is used for phospha

DedPeter [7]

Answer:

The correct insulin pathway is described as under:

2. Binding of insulin to the alpha subunit of the insulin receptor

8. Activation of insulin receptor tyrosine kinase

3. Phosphorylation of IRS proteins

6. Phosphorylation of phosphinositide 3-kinase (PI-3K)

4. Conversion of PIP2 to PIP3

7. Activation of PIP3-dependent protein kinase B (PDK1)

5. Glut4 receptors transported to the cell membrane

Explanation:

The insulin signaling pathway is described as under:

RTK (receptor tyrosine kinases) which is a receptor for insulin is an extracellular receptor but in contrast to other cell surface receptors it is catalytic in nature. In the absence of insulin (ligand), it is monomeric but as soon as it gets activated (activation occurs upon ligand binding), it undergo dimerization. It leads to auto-phosphorylation in it's tyrosine residue which subsequently leads to phosphorylation of tyrosine residue of other receptors. Such hyper-phosphorylated receptor have high affinity with enzyme/molecule like IRS protein which have SH2 domain . IRS down stream activates phosphinositide 3-kinase (PI-3K). This enzyme converts component of animal cell membrane PIP2 into PIP3. PIP3 also remains membrane bound but it has the potential to phosphorylate another enzyme named as PIP3-dependent protein kinase B (PDK1). Further, PDK1 leads to the activation of Akt or PK-B. Akt is a serine-threonine kinase which ultimately leads to the recruitment of Glut4 receptors on cell membrane for uptake of more and more glucose into the cell.

Note: Apart from this Akt also phosphorylates another protein named as FOXO which ultimately causes cell growth, Akt can also phosphorylate BAD protein so as to restrict cell apoptosis or we can say it leads to cell survival, Akt also leads to translation in a cell with the help of mTOR raptor etc.

5 0

3 years ago

I've been stuck on this question for quite a while now need some help best if I can get an answer with explanation

mart [117]

Answer:

B is most probably the right answer since it has the both hydrophollic and characteristics.

Not 100% sure though

4 0

3 years ago

If you boil hydrogen peroxide does it then become just water?

luda_lava [24]

Answer:

they will only become water if there are no other molecules to react with it.

(does that help)

Explanation:

6 0

3 years ago

A female fly that has miniature wings and sepia eyes is crossed with a male that has normal wings and is homozygous for red eyes

Eduardwww [97]

Answer and Explanation:

The gene that expresses the size of the wing is X-linked. The dominant allele expresses long wings, XM, while the recessive allele expresses miniature wings, Xm.

The gene that expresses the color of the eyes is autosomal. The dominant allele expresses red color, S, and the recessive allele expresses sepia color, s.

A female fly that has miniature wings and sepia eyes (XmXm ss) is crossed with a male that has normal wings and is homozygous for red eyes (XMY SS).

The F1 are intercrossed to produce the F2.

1º Cross:

Parental) XmXm ss x XMY SS

Gametes) Xms Xms Xms Xms

XMS XMS YS YS

Punnet Square) Xms Xms Xms Xms

XMS XMXmSs XMXmSs XMXmSs XMXmSs

YS XmY Ss XmY Ss XmY Ss XmY Ss

F1) 1/2 or 50% of the progeny are females and the other 1/2 or 50% are males

100% of the females (1/2 or 50% of the progeny) are long-winged and red-eyed

100% of the males (1/2 or 50% of the progeny) are miniature.winged and red-eyed.

2º Cross:

Parental) XMXm Ss x XmY Ss

Gametes) XMS XMs XmS Xms

XmS Xms YS Ys

Punnet Square) XMS XMs XmS Xms

XmS XMXm SS XMXm Ss XmXm SS XmXm Ss

Xms XMXm Ss XMXm ss XmXm Ss XmXm ss

YS XMY SS XMY Ss XmY SS XmY Ss

Ys XMY Ss XMY ss XmY Ss XmY ss

F2) 8/16=4/8=1/2 or 50% of the progeny are females and the other 1/2 or 50% are males

Females (8/16):

3/8 of the females are long-winged and red-eyed, XMX- S-

1/8 of the females are long-winged and sepia-eyed, XMX- ss

3/8 of the females are miniature-winged and red-eyed, XmXm S-

1/8 of the females are miniature-winged and sepia-eyed, XmXm ss

Males (8/16):

3/8 of the males are long-winged and red-eyed, XMY S-

1/8 of the males are long-winged and sepia-eyed, XMY ss

3/8 of the males are miniature-winged and red-eyed, XmY S-

1/8 of the males are miniature-winged and sepia-eyed, XmY ss

Note: The symbol "-" means that in its place might be a recessive allele or a dominant allele. For example, S- means that it might be SS or Ss.

4 0

3 years ago