What cycle do the light-independent reactions use to turn carbon dioxide into glucose?
2 answers:
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Answer:
Explanation:
<u>Given that:</u>
ΔMNO ≅ ΔPQR
That means
M ↔ P
N ↔ Q
O ↔ R
So,
∠P ≅ ∠M
Given that P = 3x + 20.4 and M = 5x - 19
3x + 20.4 = 5x - 19
Add 19 to both sides
3x + 20.4 + 19 = 5x
3x + 39.4 = 5x
Subtract 3x to both sides
39.4 = 5x - 3x
39.4 = 2x
2x = 39.4
Divide both sides by 2
x = 19.7
<u>Given that:</u>
P = 3x + 20.4
P = 3(19.7) + 20.4 (x = 19.7)
P = 59.1 + 20.4
P = 79.5°
Hope this helped!
<h3>~AH1807</h3>