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Aleonysh [2.5K]
4 years ago
8

Kingbird Company uses the LCNRV method, on an individual-item basis, in pricing its inventory items. The inventory at December 3

1, 2020, consists of products D, E, F, G, H, and I. Relevant per unit data for these products appear below. Item D Item E Item F Item G Item H Item I Estimated selling price $146 $134 $116 $110 $134 $110 Cost 92 98 98 98 61 44 Cost to complete 37 37 31 43 37 37 Selling costs 12 22 12 24 12 24.Using the LCNRV rule, determine the proper unit value for statement of financial position reporting purposes at December 31, 2014, for each of the inventory items above.

Business
1 answer:
hodyreva [135]4 years ago
5 0

Explanation:

As we know that the inventory should be recorded at the lower cost or net realizable value whichever is lower

And, the same is shown on the attachment which is attached below:

The net realizable value for each products is computed by

= D - C - E

The DCE are the rows of the attached spreadsheet

And, the proper unit value for each products is as follows

Product        Lower of cost or NRV  

D                  92

E                   75

F                   73

G                  43

H                  61

I                    44

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Which of the following actions has the best potential for experiencing economies of scope?
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Correct option is D.

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Explanation:

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3 years ago
Credit card debt. The average credit card debt for college seniors in $3262. If the debt is normally distributed with a standard
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  • 0.98 approximately
  • 0.25 approximately
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standard deviation by which debt is distributed  = $1100

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A)  probability that senior owes at least $1000

P (x ≥ 1000 ) = P ( Z ≥ \frac{1000- \alpha }{\beta }  )

where \alpha = average credit card debt = $3262

\beta = standard deviation = $1100

Z = random variable representing credit card debt for college seniors

back to equation P ( Z ≥ \frac{1000- 3262}{1100} )

therefore  P ( z ≥ -2.06 )

                 1 - p ( z ≤ -2.06 )

therefore probability of the senior owing $1000 = 1 - 0.0199 = 0.9801

B) probability that senior owes more than $4000

p ( x ≥ 4000) = P ( Z ≥ \frac{4000 - \alpha }{\beta } )

                     = P ( Z ≥ \frac{4000 - 3262}{1100} )

                     = 1 - p ( Z ≤ 0.67 ) therefore probability that senior owes more than $4000 = 1 - 0.7468 = 0.2514

C ) Probability that the senior owes between $300 and $4000

P ( 3000 ≤ x ≤ 4000) = P ( \frac{3000 - \alpha }{\beta } ≤ Z ≤ \frac{4000 - \alpha }{\beta } )

                                  = P ( \frac{3000 - 3262}{1100} ≤ z ≤ \frac{4000 - 3262}{1100} )

                                  = P ( - 0.24 ≤ z ≤ 0.67 )  

                                 = p ( z ≤ 0.67 ) - p ( z ≤ - 0.24 )        

                                 = 1 - p ( z ≥ 0.67 ) - 1 - p ( z ≥ -0.24 )

                                 = 0.7846 - 0.4052 = 0.3434                  

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• the company is a legal entity.  

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