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4 years ago

Which of the following statements about metallic bond are correct?

1 answer:

4 0

2 and 3 are true. Metals are malleable because they don't bond tightly, or they have a "sea" of electrons that allow the atoms to move about freely. The more electrons that are available to bond, the more those atoms are attracted, causing a stronger bond. If you have any questions about this, please let me know!

You might be interested in

What is the h concentration in a solution with a ph of 1.25

lyudmila [28]

Answer:

0.056 M

Explanation:

To calculate the concentration of h we must use the following formula:

10^-pH

So lets plug in our pH:

10⁻¹.²⁵

When we plug this into our calculator our answer is

0.056 M

5 0

3 years ago

Read 2 more answers

As fuel is burned in an airplane, it seems to disappear from the tank, suggesting that matter is destroyed during the reaction.

gregori [183]

Answer:

Well we know that matter is neither created nor destroyed by chemical reactions or physical transformations. It is not destroyed it simply was converted to gas. =D

6 0

3 years ago

Question 27 Unsaved

lina2011 [118]

Answer:4)Wind energy can harm migrating birds.

Explanation:

3 0

4 years ago

What is the % dissociation of a solution of acetic acid if at equilibrium the solution has a pH = 4.74 and a pKa = 4.74?

Ymorist [56]

Answer:

$\% diss = 50\%$

Explanation:

Hello there!

In this case, when considering weak acids which have an associated percent dissociation, we first need to set up the ionization reaction and the equilibrium expression:

$HA\rightleftharpoons H^++A^-\\\\Ka=\frac{[H^+][A^-]}{[HA]}$

Now, by introducing x as the reaction extent which also represents the concentration of both H+ and A-, we have:

$Ka=\frac{x^2}{[HA]_0-x} =10^{-4.74}=1.82x10^{-5}$

Thus, it is possible to find x given the pH as shown below:

$x=10^{-pH}=10^{-4.74}=1.82x10^{-5}M$

So that we can calculate the initial concentration of the acid:

$\frac{(1.82x10^{-5})^2}{[HA]_0-1.82x10^{-5}} =1.82x10^{-5}\\\\\frac{1.82x10^{-5}}{[HA]_0-1.82x10^{-5}} =1\\\\$

$[HA]_0=3.64x10^{-5}M$

Therefore, the percent dissociation turns out to be:

$\% diss=\frac{x}{[HA]_0}*100\% \\\\\% diss=\frac{1.82x10^{-5}M}{3.64x10^{-5}M}*100\% \\\\\% diss = 50\%$

Best regards!

6 0

3 years ago

To form a salt compound, the acid contributes the __ ion, and the base contributes the ___ ion

cupoosta [38]

To form a salt compound, the acid contribute a NON METAL ION and the base contributes a METAL ION.
In chemistry, acid and base react together to form salt and water only. For the salt formed, the positive metal ion comes from the base while the negative non metal ion comes from the acid.

8 0

3 years ago