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Alekssandra [29.7K]
3 years ago
10

In the name carbon dioxide, the prefix of the second word indicates that a molecule of carbon dioxide contains

Chemistry
1 answer:
svetlana [45]3 years ago
3 0
Two oxygen atoms, di means two, oxide means oxygen. 
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After a tree is cut down with a chainsaw, it is impossible to put the tiny wood chips back together
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Explanation:

4C_2H_5O_2N(s) + 9O_2(g)\rightarrow 8CO_2(g) + 10H_2O(l) + 2N_2(g) ,\Delta H^{rxn} =-3896 kJ/mol

Standard enthalpy of formation of oxygen gas= \Delta H_{f,O_2}=0

Standard enthalpy of formation of carbon dioxide= \Delta H_{f,CO_2}=-393.5 kJ/mol

Standard enthalpy of formation of water = \Delta H_{f,H_2O}=-285.8 kJ/mol

Standard enthalpy of formation of nitrogen gas= \Delta H_{f,N_2}=0

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Enthalpy of the reaction = H_{rxn}=-3896 kJ/mol

H_{rxn} =

=8\times \Delta H_{f,CO_2} +10\times \Delta H_{f,H_2O}+2\times \Delta H_{f,N_2} - (4\times \Delta H_{f,gly}+9\times \Delta H_{f,O_2})

-3896 kJ/mol=8\times (-393.5 kJ/mol)+ 10\times (-285.8 kJ/mol)+0 - (4\times \Delta H_{f,gly} +0)

On rearranging :

4\times \Delta H_{f,gly}=8\times (-393.5 kJ/mol)+ 10\times (-285.8 kJ/mol)+ 3896 kJ/mol

\Delta H_{f,gly}=\frac{-2149 kJ/mol}{4}=-537.25 kJ/mol

-537.25 kJ/mol is the standard enthalpy of formation of solid glycine.

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