Answer:
Structures are given below.
Explanation:
- Treatment of 2-bromo-2-methylbutane with KOH in ethanol will give elimination of HBr through E2 mechanism.
- H atoms adjacent to Br will be eliminated.
- 2-bromo-2-methylbutane has two possible adjacent H atoms that can be eliminated giving mixture of products.
- Product of this elimination reaction is alkene. Here saytzeff fule is followed during elimination. So most substituted alkene will be major product.
- Structure of alkenes are given below.
Answer:
0.92322835
Explanation:
0.92322835 rounded= 0.9 or 0.92
Answer:
Callie expect 600 molecules of CO2 to have been released as a waste during the same amount of time.
Explanation:
During cellular respiration 1 molecule of glucose undergoes oxidation to form 6 molecules of CO2 as a waste product.
According to the question callie determined that the germinating corn seed had utilized 100 molecules of glucose.
So 100 molecules of glucose will release 100×6=600 molecules of CO2 as a waste product.
Yes it does, its derived from the greek name for beryl, or beryllo
