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Molodets [167]
3 years ago
6

Hydration of alkynes (via oxymercuration) gives good yields of single compounds only with symmetrical or terminal alkynes. draw

the major organic product(s) formed when hex-2-yne undergoes hydration in the presence of hgso4 and h2so4

Chemistry
1 answer:
nikitadnepr [17]3 years ago
3 0
Hex-2-yne is not symmetrical alkyne, So, it will give two products namely Hexan-3-one and Hexan-2-one.
The reaction along with mechanism is shown below,

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pav-90 [236]

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6 0
3 years ago
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Which type of energy refers to the sum of potential and kinetic energies in the particles of a substance?
MrRa [10]

Explanation:

the sum of PE and KE is mechanical energy this means energy during motion and position I think the answer is motion and stored or it may be internal

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3 years ago
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How do you balance Sb+I2=SbI3 show work please
egoroff_w [7]

Answer:

 2Sb   +    3I₂    →    2SbI₃

Explanation:

The reaction expression we need to balance is:

         Sb   +    I₂    →    SbI₃

To balance this expression, we need to assign the variables a,b and c to each specie as the coefficient that will balance the expression.

              aSb   +    bI₂    →    cSbI₃

Conserving Sb :  a  = c

                      I :   2b  = 3c

let a  = 1, c  = 1,  b  = \frac{3}{2}  

   Multiply through by 2;

 a  = 2, b  = 3  and c  = 2

         2Sb   +    3I₂    →    2SbI₃

7 0
3 years ago
A sample of hydrogen gas is collected over water at 25°C. The vapor pressure of water at 25°C is 23.8 mmHg. If the total pressur
Illusion [34]
The partial pressure of the gas will be the total pressure minus the vapor pressure.  523.8-23.8=500mmHg.  This makes sense due to the fact that the idea of partial pressures still works even with vapor pressure since vapor pressure is just the partial pressure of water vapor (23.8mmHg) in the container which is added to the partial pressure of hydrogen gas (500mmHg) to make a total pressure of 523.8mmHg.
I hope this helps.  Let me know in the comments if anything is unclear.
4 0
3 years ago
PLZ SEE ATTACHED AND I WOULD REALLY APPRECIATE IT! ANYONE GOOD WITH CHEM
Alenkasestr [34]

Answer : The value of \Delta H_{rxn} for the reaction is, -390.3 kJ

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The main chemical reaction is:

CH_4(g)+4Cl_2(g)\rightarrow CCl_4(g)+4HCl(g)    \Delta H_{rxn}=?

The intermediate balanced chemical reaction are:

(1) C(s)+2H_2(g)\rightarrow CH_4(g)     \Delta H_1=-74.6kJ

(2) C(s)+2Cl_2(g)\rightarrow CCl_4(g)     \Delta H_2=-95.7kJ

(3) H_2(g)+Cl_2(g)\rightarrow 2HCl(g)     \Delta H_2=-184.6kJ

Now we are reversing reaction 1, multiplying reaction 3 by 2 and then adding all the equations, we get :

(1) CH_4(g)\rightarrow C(s)+2H_2(g)     \Delta H_1=74.6kJ

(2) C(s)+2Cl_2(g)\rightarrow CCl_4(g)     \Delta H_2=-95.7kJ

(3) 2H_2(g)+2Cl_2(g)\rightarrow 4HCl(g)     \Delta H_2=2\times (-184.6kJ)=-369.2kJ

The expression for enthalpy change for the reaction will be,

\Delta H_{rxn}=\Delta H_1+\Delta H_2+\Delta H_3

\Delta H_{rxn}=(74.6kJ)+(-95.7kJ)+(-369.2kJ)

\Delta H_{rxn}=-390.3kJ

Therefore, the value of \Delta H_{rxn} for the reaction is, -390.3 kJ

8 0
3 years ago
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