n(A-B) denotes elements which are in A but not in B
n(Au B) denotes elements in A and B
n(AnB) denotes elements that are common in A and B
Now I will add one more set
n(B-A) which denotes elements in B but not in A
So, n(AuB) = n(A-B) + n( B-A) +n(AnB)
70 = 18 +n(B-A) + 25
70 = 43 + n(B-A)
n(B-A) = 70-43
n(B-A) = 27
So, n(B) = n( B-A) + n( AnB)
= 27+25
= 52
Answer:
(6 + 3/n) -8
Step-by-step explanation:
Answer: Can you explain more? you have to calculate it by an theorm
Step-by-step explanation:
Step-by-step explanation:
a. 2(y-8)
= 2y-16
b. 3(x-5)
= 3x-15
c.6(b-4)
= 6b-32
d.7(d-2)
= 7d-14
e.5(2-y)
= 10-5y
f.3(4-t)
= 12-3t
g.5(b-a)
=5b-5a
h.7(2-h)
= 14-7h
