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Alex777 [14]
2 years ago
10

Work out (5.32 x 10^-7): (2.5 x 10^-5)Give your answer in standard form​

Mathematics
1 answer:
Mrrafil [7]2 years ago
8 0

Answer:

1.33×10^-6

Step-by-step explanation:

5.32 x 10^-7= 5.32×10^(-5-2)= 5.32×10^-2×10^(-5)

=0.0532×10^-5

(0.0532×10^-5) (2.5 x 10^-5)

0.0532×2.5 × 10^-5

0.133×10^-5= 1.33×10^-1 ×10^-5

1.33×10^-6

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A point H is 20m away from the foot of a tower on the same horizontal ground. From the point H, the angle of elevation of the po
astra-53 [7]

Answer:

a. See Attachment 1

b. PT = 12.3\ m

c. HT = 31.1\ m

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Step-by-step explanation:

Calculating PT

To calculate PT, we need to get distance OT and OP

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We have to consider angle 50, distance OH and distance OT

The relationship between these parameters is;

tan50 = \frac{OT}{20}

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OT = 23.836

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We have to consider angle 30, distance OH and distance OP

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Multiply both sides by 20

20 * tan30 = \frac{OP}{20} * 20

20 * tan30 = OP

20 * 0.5774= OP

11.548 = OP

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--------------------------------------------------------

Calculating the distance between H and the top of the tower

This is represented by HT

HT can be calculated using Pythagoras theorem

HT^2 = OT^2 + OH^2

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HT^2 = 20^2 + 23.836^2

HT^2 = 400 + 568.154896

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Take Square Root of both sides

HT = \sqrt{968.154896}

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--------------------------------------------------------

Calculating the position of H

This is represented by OH

See Attachment 2

We have to consider angle 50, distance OH and distance OT

The relationship between these parameters is;

tan50 = \frac{OH}{OT}

Multiply both sides by OT

OT * tan50 = \frac{OH}{OT} * OT

OT * tan50 = {OH

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Substitute OT = 23.836

23.836 * 1.1918 = OH

28.4= OH

OH = 28.4\ m<em> (Approximated)</em>

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