Answer:
B. ![\frac{450}{10000}](https://tex.z-dn.net/?f=%5Cfrac%7B450%7D%7B10000%7D)
Step-by-step explanation:
The probability of rolling a 2 is <u>10 out of 100</u> (18+10+12+25+3+32), or 10%.
The probability of the coin landing heads up is <u>45 out of 100</u>. or 45%.
Multiply both probabilities together.
×![\frac{45}{100}](https://tex.z-dn.net/?f=%5Cfrac%7B45%7D%7B100%7D)
![\frac{450}{10000}](https://tex.z-dn.net/?f=%5Cfrac%7B450%7D%7B10000%7D)
I hope this helps!
pls ❤ and give brainliest pls
In its decimal form, it says ' 64 / 100 '.
In order to change it to its lowest terms, we look to see whether the
numerator and denominator have a common factor greater than ' 1 '.
If they do, then we can divide numerator and denominator by their
common factor, and have the same fraction in lower terms.
The common factors of 64 and 100 are 1, 2, and 4 .
We could divide top and bottom by 2, but that wouldn't finish the job.
It's always best to divide them by their <u>greatest</u> common factor, and
once you do that, you're done.
Dividing the numerator and denominator both by 4,
we get the fraction in its lowest terms:
0.64 = 64/100 = <em>16/25</em>
Answer:
1/6
Step-by-step explanation:
$50 is 1/6 of $300
(I think this is what you meant. The question was kind of confusing.)
Answer:
![\sqrt{2\cdot 17}](https://tex.z-dn.net/?f=%5Csqrt%7B2%5Ccdot%2017%7D)
Step-by-step explanation:
The magnitude of a vector is the length of the vector itself.
Given a bi-dimensional vector, the magnitude of the vector is given by:
![|v|=\sqrt{v_x^2+v_y^2}](https://tex.z-dn.net/?f=%7Cv%7C%3D%5Csqrt%7Bv_x%5E2%2Bv_y%5E2%7D)
where
is the x-component of the vector
is the y-component of the vector
The vector in this problem is
![v=(-5,3)](https://tex.z-dn.net/?f=v%3D%28-5%2C3%29)
Therefore its components are
![v_x=-5\\v_y=3](https://tex.z-dn.net/?f=v_x%3D-5%5C%5Cv_y%3D3)
And so, the magnitude of the vector is:
![|v|=\sqrt{(-5)^2+(3)^2}=\sqrt{25+9}=\sqrt{34}=\sqrt{2\cdot 17}](https://tex.z-dn.net/?f=%7Cv%7C%3D%5Csqrt%7B%28-5%29%5E2%2B%283%29%5E2%7D%3D%5Csqrt%7B25%2B9%7D%3D%5Csqrt%7B34%7D%3D%5Csqrt%7B2%5Ccdot%2017%7D)