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MissTica
4 years ago
7

What is the approximate distance between points A and B?

Mathematics
2 answers:
shepuryov [24]4 years ago
7 0

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-2}~,~\stackrel{y_1}{-3})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{4})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{[1-(-2)]^2+[4-(-3)]^2}\implies d=\sqrt{(1+2)^2+(4+3)^2} \\\\\\ d=\sqrt{9+49}\implies d=\sqrt{58}\implies d\approx 7.62

Licemer1 [7]4 years ago
5 0

Answer:

7.62 units

Step-by-step explanation:

We are given that

The coordinates of point A is at (1,4).

The coordinates of point B is at (-2,-3).

We have to find the approximate distance between A and B.

Distance formula:\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using this formula we will find the distance between  A and B.

AB=\sqrt{(-2-1)^2+(-3-4)^2}

Distance between A and B=\sqrt{49+9}=\sqrt{58}

Distance between A and B=7.62 units

Hence, the approximate distance between points A and  B=7.62 units

Option C is true.

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Answer: 23 in

Step-by-Step Explanation:

Height (h) = 18 in
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We know,
Area of a Triangle = 1/2 * b * h

Therefore,
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A rose garden Is formed by jolning a rectangle and a semicircle, as shown below. The rectangle Is 23 ft long and 14 ft wide.Find
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Answer:

Area of the garden:

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Explanation:

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Since the width of the rectangle is 14 ft, so the diameter(d) of the semicircle is also 14 ft.

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A_{sc}=\frac{\pi r^2}{2}=\frac{3.14*\left(7\right)^2}{2}=\frac{3.14*49}{2}=\frac{153.86}{2}=76.93\text{ ft}^2

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We can now determine the area of the garden by adding the area of the semicircle and that of the rectangle together;

\begin{gathered} Area\text{ of the garden = Area of semi circle + Area of rectangle } \\ =76.93+322 \\ =398.93\text{ ft}^2 \end{gathered}

Therefore, the area of the garden is 398.93 ft^2

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