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amid [387]
4 years ago
15

Which equation can be used to find the measure of an angle that is supplementary to ∠

Mathematics
1 answer:
Rus_ich [418]4 years ago
5 0
I believe that the best answer to the choices given in your question is
<span>B m∠EOF + m∠EOD = 180 %DegreeSign%</span>

Thank you for posting here at Brainly.I hope I have answered your question. Have a nice day ahead. 
You might be interested in
A construction worker needs to determine the volume of a sandpille in a construction yard as shown
postnew [5]
Answer:
6580cm
Step-by-step explanation:
The answer is 6580cm because....
Step one First let's figure out what the smaller shape's volume is. To do so we need to multiply ( LxWxH ) so 6x5x? it does not list what the height is so we know it has the same height as the larger shape and it's height is 14cm so we will use 14cm. 6x5x14=420cm
Step two Now lets find the Volume of the larger shape. So lets do LxWxH so Lx?x14 it does not give us the length so we need to add up all of the numbers along the line. We got 7cm then 5 from the bottom of the smaller shape and 10cm. all ads up to 22cm so 20x22x14=6160
Finally we add up the following shapes Volume which are 6160+420=6580cm
3 0
3 years ago
let t : r2 →r2 be the linear transformation that reflects vectors over the y−axis. a) geometrically (that is without computing a
tangare [24]

(a) ( 1, 0 ) is the eigen vector for '-1' and ( 0, 1 ) is the eigen vector for '1'.

(b)  two eigen values of 'k' = 1, -1

for k = 1, eigen vector is \left[\begin{array}{c}0\\1\end{array}\right]

for k = -1 eigen vector is \left[\begin{array}{c}1\\0\end{array}\right]

See the figure for the graph:

(a) for any (x, y) ∈ R² the reflection of (x, y) over the y - axis is ( -x, y )

∴ x → -x hence '-1' is the eigen value.

∴ y → y hence '1' is the eigen value.

also, ( 1, 0 ) → -1 ( 1, 0 ) so ( 1, 0 ) is the eigen vector for '-1'.

( 0, 1 ) → 1 ( 0, 1 ) so ( 0, 1 ) is the eigen vector for '1'.

(b) ∵ T(x, y) = (-x, y)

T(x) = -x = (-1)(x) + 0(y)

T(y) =  y = 0(x) + 1(y)

Matrix Representation of T = \left[\begin{array}{cc}-1&0\\0&1\end{array}\right]

now, eigen value of 'T'

T - kI =  \left[\begin{array}{cc}-1-k&0\\0&1-k\end{array}\right]

after solving the determinant,

we get two eigen values of 'k' = 1, -1

for k = 1, eigen vector is \left[\begin{array}{c}0\\1\end{array}\right]

for k = -1 eigen vector is \left[\begin{array}{c}1\\0\end{array}\right]

Hence,

(a) ( 1, 0 ) is the eigen vector for '-1' and ( 0, 1 ) is the eigen vector for '1'.

(b)  two eigen values of 'k' = 1, -1

for k = 1, eigen vector is \left[\begin{array}{c}0\\1\end{array}\right]

for k = -1 eigen vector is \left[\begin{array}{c}1\\0\end{array}\right]

Learn more about " Matrix and Eigen Values, Vector " from here: brainly.com/question/13050052

#SPJ4

6 0
1 year ago
Find the mean, median, and mode for the data set below.<br> weights of books (oz): 10 9 9 14 13 11
ziro4ka [17]

Answer:

Mean: 11

Median: 10.5

Mode: 9

3 0
3 years ago
How many unit cubes will fit in the rectangular prism? <br> A) 9 B) 36 C) 40 D) 45
antiseptic1488 [7]

Answer:

D) 45

Step-by-step explanation:

5 x 3 x 3 = 45

8 0
3 years ago
Just answer #2 plz for brainlest
AlexFokin [52]

n>-6 and n<3 (there's your answer my friend)

8 0
3 years ago
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