The expression is a perfect square trinomial if and only if c = 121.
<h3>
How to get the value of c?</h3>
A perfect square trinomial is written as:
(a + b)^2 = a^2 + b^2 + 2ab
In this case, we have:
t^2 - 22t + c
We can rewrite this as:
t^2 - 2*11*t + c
Then we have:
a = t
b = -11
And we will have that:
c = b^2 = (-11)^2 = 121
Then we have:
t^2 - 2*11*t + 121
Which is a perfect square trinomial:
(t - 11)^2 = t^2 - 22t + 121
Learn more about perfect squares:
brainly.com/question/1538726
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