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erica [24]
4 years ago
14

Ann lives in Princeton, New Jersey, and commutes by train each day to her job in New York City (20 round trips per month). When

the price of a round trip goes up from $10 to $20, she responds by consuming exactly the same number of trips as before, while spending $200 per month less on restaurant meals. a.Does the fact that her quantity of train travel is completely unresponsive to the price increase imply that Ann is not a rational consumer? b.Explain why an increase in train travel might affect the amount she spends on restaurant meals.
Business
1 answer:
natka813 [3]4 years ago
8 0

Answer:

No; Because the higher price of round trips has reduced her purchasing power

Explanation:

Anne commutes by train each day to her job. The price of a round trip increased to $20 from $10. Though, the number of round trips consumed remains the same.

With an increase in the price of round trips instead of reducing the number of round trips, she consumes the same but reduces spending on restaurant meals.

This does not make Anne irrational as a consumer. The marginal utility of each dollar spent on round trips is still higher than other goods Anne consumes, so she is not reducing the consumption of round trips.

However, the increase in price has reduced her purchasing power. As a result, she is reducing the consumption of restaurant meals which is probably providing the lower marginal utility of each dollar spent on it.

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3 years ago
An oil refinery is located on the north bank of a straight river that is 3km wide. A pipeline is to be constructed from the refi
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Answer:

$6,598,076.21

Explanation:

<h2>THE KEY IS TO FIND OUT THE COST FUNCTION, the calculations are very easy!!!</h2><h2></h2><h3>In order to find the cost function, take a look at the drawing attached. </h3>

We can see the river (sort of) that is 3 km wide and the storage tanks on the other side of the river 8 km apart.

<h3 />

Laying pipes under (across) the river costs 1,000,000 the km & laying pipes over land costs 500,000 per km.

<h3 /><h3>So basically the cost function is 1,000,000 multiplied by something plus 500,000 multiplied by another something.</h3><h3 />

The distance across the river can be found by using Pythagoras Theorem. A side is 3 km the other is unknown, so we call it X. And it is equal to:

\sqrt{3^{2} +x^{2}}=\\\sqrt{9 +x^{2}}

And we multiply it by 1,000,000; the cost of laying pipe under the river, the we get:

1000000\sqrt{9+x^{2}

The distance over the land is (8-x), as we can see in the drawing. So we multiply it by its cost, 500,000. And we get 500,000(8-x).

So the cost function f(x) would be:

f(x)=1000000\sqrt{9+x^{2}} + 500000(8-x)

<h2>From here, we just have to differentiate and the derivative found must be equal to zero in order to minimize cost. </h2><h3>The value of x when the derivative is zero is plugged in the original function to get the cost.</h3><h3 /><h2>LET'S DO THIS</h2>

f(x)=1000000\sqrt{9+x^{2}} + 500000(8-x)\\f(x)=1000000(9+x^{2})^{1/2}+4000000-500000x\\f'(x)=\frac{1}{2} 1000000(9+x^{2})^{-1/2}(2x)-500000\\\\f'(x)=\frac{1000000x}{\sqrt{9+x^2}}  - 500000

<h2>f'(x)=0</h2>

f'(x)=\frac{1000000x}{\sqrt{9+x^2}}  - 500000=0\\\frac{1000000x}{\sqrt{9+x^2}}  = 500000\\\frac{2x}{\sqrt{9+x^2}}  = 1\\2x={\sqrt{9+x^2}}\\4x^2=9+x^2\\3x^2=9\\x^2=3\\x=\sqrt{3} \\

And we plug square root of 3 in the original cost function  ad we get

f(\sqrt{3} )=1000000\sqrt{9+x^{2}} + 500000(8-x)\\f(\sqrt{3})=1000000\sqrt{9+(\sqrt{3} )^{2}} + 500000(8-(\sqrt{3}))\\f(\sqrt{3})=1000000\sqrt{9+3} + 500000(8-(\sqrt{3}))\\f(\sqrt{3})=1000000\sqrt{12}+500000(6.27)\\f(\sqrt{3})=1000000(3.46)+500000(6.27)\\f(\sqrt{3})=3464101.62+3133974.60\\f(\sqrt{3})=6598076.21\\

<h2>so the minimal cost is $6,598,076.21</h2><h2 /><h3 />

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3 years ago
Lincoln Park Co. has a bond outstanding with a coupon rate of 5.73 percent and semiannual payments. The yield to maturity is 6.7
Natalija [7]

Answer:

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Explanation:

Giving the following information:

Coupon rate= 0.0573/2= 0.02865

YTM= 0.067/2= 0.0335

The bond matures in 23 years.

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<u>To calculate the bond price, we need to use the following formula:</u>

Bond Price​= cupon*{[1 - (1+i)^-n] / i} + [face value/(1+i)^n]

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Bond Price​= 1,334.76 + 439.29

Bond Price​= $1,774.05

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3 years ago
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