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EleoNora [17]
3 years ago
11

Anyone know the answer to this algebra 2 problem?

Mathematics
1 answer:
marin [14]3 years ago
6 0

Answer:

C

Step-by-step explanation:

just evaluate the equation with numbers and you'll find it out

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Find the next 3 terms. J30, J31, A31, S30
nikdorinn [45]

Answer:

Next 3 terms 031, N30, D31

Step-by-step explanation:

J30, J31, A31, S30

The above series represent the

first letter of the month and the days in it

J30= June which have 30 days

J31= July which has 31 days

A31= August which have 31 days

S30= September which have 30 days

30 days hath September, April, June and November. All the rest have 31 except February alone which has but 28 or 29 days

The next 3 terms of the series J30, J31, A31, S30 are 031, N30, D31

6 0
4 years ago
What is the equation of a circle with a center of (1,-4) and a radius of <br> 22?
Ilya [14]
<span>Center (1,-4) and radius =22
General form of a circle is
</span><span>(x -a)² + (y -b)² = r²
where a & b are the (x, y) points of the center
</span>
<span>(x -1)² + (y - - 4)² = 22²

Source:
http://1728.org/circle.htm

</span>
7 0
3 years ago
honestly i'm ready to give up, I need help but nobody's helping and it's extremely stressful so could someone please help. and n
Keith_Richards [23]

Answer:

b-d-e

Step-by-step explanation:

I think i could completly wrong

* someone sent u p-orn?*

7 0
3 years ago
David goes into a candy store with $5.00. he buys 9 peppermints for $0.15 each, and some sour candies. each sour candy costs $0.
ANEK [815]
Step one. $5.00 - 9 peppermints
= $5.00 - $1.35
= $3.65
Step two. Figure out how many 25 cents are in $3.65.
$3.65 divided by .25
= 14.6 So David can buy 14 sour candies.
7 0
3 years ago
Please help me :
Andrews [41]

<u>(x-5)²+(y-5)²=36</u>

Answer:

Solution given:

radius [r]=6 units

centre[h,k]=(5,4)

we have

the equation of a circle is;

(x-h)²+(y-k)²=r²

(x-5)²+(y-5)²=6²

<u>(</u><u>x-5</u><u>)</u><u>²</u><u>+</u><u>(</u><u>y-5</u><u>)</u><u>²</u><u>=</u><u>3</u><u>6</u><u> </u><u>is</u><u> </u><u>a</u><u> </u><u>required</u><u> </u><u>equation</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>circle</u><u>.</u>

8 0
3 years ago
Read 2 more answers
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