Solve for x. −2x−1+3x=7 x=−2 x=−1 x = 6 x = 8

Probability is typically expressed as a fraction where the numerator is the number of desired outcomes and the denominator is the total number of outcomes. In this case the suitable parts is the desired outcome and the total shipment is the total parts:

$\frac{suitable}{total}=\frac{15}{20}=\frac{3}{4}=0.75$

The probability the both the first and second part are suitable:

$\frac{15}{20}*\frac{14}{19}=\frac{210}{380}=0.5526$

Since the probability of getting a suitable part the first time is 15/20, then there is one less suitable part and one less part overall to choose on the second time, or 14/19.

Lastly, the probability of choosing a suitable part the first time is again 15/20, but the second part not being suitable would be 5/19:

4 0

3 years ago

The table shows the distances traveled by a paper airplane.

BabaBlast [244]

Answer:

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Writing Equations of Parallel Lines

Nookie1986 [14]

Answer:

The slope of the parallel line to the given line is $-\frac{1}{4}$

The equation of the parallel line to the given line and passes through the given point is y + 4 = $-\frac{1}{4}$ (x + 2)

The y-intercept of the parallel line to the given line and passes through the given point is $-\frac{9}{2}$

Step-by-step explanation:

The rule of the slope of the line that passes through points (x1, y1) and (x2, y2) is m = $\frac{y2-y1}{x2-x1}$

The point-slope form of the linear equation is y - y1 = m(x - x1), where m is the slope and (x1, y1) is a point on the line

The slope-intercept form of the linear equation is y = m x + b, where m is the slope and b is the y-intercept

Parallel lines have the same slopes and different y-intercepts

In the given figure

∵ The given line passes through points (2, 6) and (-6, 8)

∴ x1 = 2 and y1 = 6

∴ x2 = -6 and y2 = 8

→ Substitute them in the rule of the slope above to find it

∵ m = $\frac{8-6}{-6-2}$ = $\frac{2}{-8}$ = $-\frac{1}{4}$

∴ The slope of the given line is $-\frac{1}{4}$

∵ Parallel lines have the same slopes

∴ The slope of the parallel line to the given line is $-\frac{1}{4}$

∵ The parallel line passes through the point (-2, -4)

∴ x1 = -2 and y1 = -4

∵ m = $-\frac{1}{4}$

→ Substitute them in the point-slope form above

∵ y - (-4) = $-\frac{1}{4}$ (x - (-2))

∴ y + 4 = $-\frac{1}{4}$ (x + 2)

∴ The equation of the parallel line to the given line and passes through

the given point is y + 4 = $-\frac{1}{4}$ (x + 2)

∵ m = $-\frac{1}{4}$

→ Substitute it in the slope-intercept form above

∴ y = $-\frac{1}{4}$ x + b

→ To find b substitute x by -2 and y by -4 (coordinates the given point)

∵ -4 = $-\frac{1}{4}$ (-2) + b

∴ -4 = $\frac{1}{2}$ + b

→ Subtract $\frac{1}{2}$ from both sides

∴ $-\frac{9}{2}$ = b

∵ b is the y-intercept

∴ The y-intercept of the parallel line to the given line and passes

through the given point is $-\frac{9}{2}$

8 0

3 years ago