Answer:
It is 40 degrees.
Step-by-step explanation:
You can start off by understanding this is not a right angle (exactly 90 degrees, think of a corner of a room) or and obtuse angle (more than 90 degrees, bigger than a right angle). With that information we know that it is an acute angle (less than 90 degrees, smaller than a right angle). With that we have 40 and 50 degrees left. When you compare the angle with the 40 degrees one, it is the same size. The angle 1 is a reflection of the triangle with the 40 degrees angle. Hope this helps :)
25/20 × 100% = 125%
125% - 100% = 25%
25% profit :)
X^2-5x-14
It is the correct answer I think
Answer:
The width of the border can be 9 feet or 3.5 feet.
Step-by-step explanation:
Let the width be x
Length of room = 10 feet
Breadth of room = 15 feet
Length of rug = 10-2x
Breadth of rug = 15-2x
Area of rug =
We are given that the area of the rug is 24 square feet.
So,
---A






Substitute x =9 in A


LHS = RHS
Substitute x = 3.5


LHS = RHS
So, The width of the border can be 9 feet or 3.5 feet.
Step-by-step explanation:






Taking sin²θ common in both numerator & denominator, We get :










<u>Hence</u><u>,</u><u> option</u><u> </u><u>(</u><u>a)</u><u> </u><u>2</u><u>/</u><u>3</u><u> </u><u>is </u><u>your</u><u> </u><u>correct</u><u> </u><u>answer</u><u>.</u>