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Alex
2 years ago
8

Find the value of the following expression 100 - 2(x + 5) when x = 10 *

Mathematics
2 answers:
Ede4ka [16]2 years ago
4 0

Answer:

70

Step-by-step explanation:

100 - 2(x + 5) = 100 - 2x - 10 = 90 -2x

90 - 2x

90 - 2×10

90 - 20 = 70

zubka84 [21]2 years ago
4 0
yep that’s correct!
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Which is the best estimate for the length of the car 4 kilometers 4tons 4kilograms 4meters
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4 meters

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3 years ago
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Sing fitness evaluations to determine fitness levels is important to __________.
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Answer:

D, All of the above.

Step-by-step explanation:

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6 0
3 years ago
Write the equation for the hyperbola with foci (–12, 6), (6, 6) and vertices (–10, 6), (4, 6).
fomenos

Answer:

\frac{(x--3)^2}{49} -\frac{(y-6)^2}{32}=1

Step-by-step explanation:

The standard equation of a horizontal hyperbola with center (h,k) is

\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1

The given hyperbola has vertices at (–10, 6) and (4, 6).

The length of its major axis is 2a=|4--10|.

\implies 2a=|14|

\implies 2a=14

\implies a=7

The center is the midpoint of the vertices (–10, 6) and (4, 6).

The center is (\frac{-10+4}{2},\frac{6+6}{2}=(-3,6)

We need to use the relation a^2+b^2=c^2 to find b^2.

The c-value is the distance from the center (-3,6) to one of the foci (6,6)

c=|6--3|=9

\implies 7^2+b^2=9^2

\implies b^2=9^2-7^2

\implies b^2=81-49

\implies b^2=32

We substitute these values into the standard equation of the hyperbola to obtain:

\frac{(x--3)^2}{7^2} - \frac{(y-6)^2}{32}=1

\frac{(x+3)^2}{49} -\frac{(y-6)^2}{32}=1

7 0
3 years ago
What is the range of g(x)?
Mila [183]

Answer:

2

Step-by-step explanation:

I just need for the points

5 0
2 years ago
What is the answer for 3{5[10+5(500-100)+399]}
notka56 [123]
Okay. Handle 500-100 first. That brings it to 3{5[10+5(400)+399]}. Next, Handle 5(400). That brings you to 3{5{10+2,000+399]}. Then handle all the addition. That leads to 3[5(2,409)]. Next, configure 5(2409). That leads to 3(12045). Then do that one which ends as 36,135 for a final answer.
5 0
3 years ago
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