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jeyben [28]
3 years ago
6

g red bell pepper seeds germinates 85% of the time. planted 25 seeds. What is the probability that 20 or more germinate

Mathematics
1 answer:
bixtya [17]3 years ago
7 0

Answer:

P(X\geq 20)= P(X=20)+P(X=21)+P(X=22)+P(X=23)+P(X=24)+P(X=25)

And replacing using the mass function we got:

P(X=20)=(25C20)(0.85)^{20} (1-0.85)^{25-20}=0.156  

P(X=21)=(25C21)(0.85)^{21} (1-0.85)^{25-21}=0.211  

P(X=22)=(25C22)(0.85)^{22} (1-0.85)^{25-22}=0.217  

P(X=23)=(25C23)(0.85)^{23} (1-0.85)^{25-23}=0.161  

P(X=24)=(25C24)(0.85)^{24} (1-0.85)^{25-24}=0.0759  

P(X=25)=(25C25)(0.85)^{25} (1-0.85)^{25-25}=0.0172  

And adding the values we got:

P(X\geq 20) = 0.8381

Step-by-step explanation:

Let X the random variable of interest, on this case we now that:  

X \sim Binom(n=25, p=0.85)  

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

We want to find the following probability:

P(X\geq 20)= P(X=20)+P(X=21)+P(X=22)+P(X=23)+P(X=24)+P(X=25)

And replacing using the mass function we got:

P(X=20)=(25C20)(0.85)^{20} (1-0.85)^{25-20}=0.156  

P(X=21)=(25C21)(0.85)^{21} (1-0.85)^{25-21}=0.211  

P(X=22)=(25C22)(0.85)^{22} (1-0.85)^{25-22}=0.217  

P(X=23)=(25C23)(0.85)^{23} (1-0.85)^{25-23}=0.161  

P(X=24)=(25C24)(0.85)^{24} (1-0.85)^{25-24}=0.0759  

P(X=25)=(25C25)(0.85)^{25} (1-0.85)^{25-25}=0.0172  

And adding the values we got:

P(X\geq 20) = 0.8381

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