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3 years ago

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The coach of a soccer team is holding tryouts and can take only 2 more players for the team. There are 8 players trying out. How

many different groups of 2 players could possibly be chosen?

1 answer:

torisob [31]3 years ago

6 0

4 different groups of 2 people

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I need help simplifying 8^3

Dafna1 [17]

8^3 = 512
8^3 also eqauls 8 x 8 x 8.
I hope I helped!

6 0

3 years ago

Read 2 more answers

The discriminant of a quadratic equation is 40. What is the nature of solutions?

RSB [31]

Answer:

It means that the roots of the quadratic equation are real and distinct

Step-by-step explanation:

Here, given the discriminant of the quadratic equation, we want to find out the nature of the solutions.

Mathematically, we can use to determine the nature of the discriminant.

By it’s formula;

D = b^2 - 4ac

We can see that the given discriminant 40 is a positive value. What this means is that the quadratic equation has roots which are real and are distinct

4 0

3 years ago

Which statement best describes the effect of replacing the function f(x) = 2x + 2 with the function g(x) = 2x - 3?

FrozenT [24]

The correct answer is: <span>The graph shifts 5 units right

Explanation:
Below is the graph attached of both the equations:

Red line: Represents f(x) = </span><span>2x + 2.
Blue line: Represents g(x) = 2x - 3.

As you can see in the graph that g(x) is shifted 5 units right to f(x).

If you move towards right by 1 unit, you have to subtract 1 from f(x) until you reach g(x) like:
2x + 2 - 1 = 2x + 1 (1 unit)
</span>2x + 1 - 1 = 2x (1 unit)
2x - 1 = 2x - 1 (1 unit)
2x - 1 -1 = 2x - 2 (1 unit)
2x -2 - 1 = 2x -3 (1 unit)

Total 5 units.

Hence the correct answer is t<span>he graph shifts 5 units right.</span>

7 0

3 years ago

Read 2 more answers

A number that divided by 3 leaves 2, divided by 5 leaves 3 and divided by 7 leaves 2. What is the number?

Bogdan [553]

X/3=2
x=6

x/5=3
x=15

x/7=2
x=14

Each time, you multiply both sides by the denominator.

Hope this helps :)

7 0

3 years ago

Which of the following is not one of the 8th roots of unity?

Anika [276]

Answer:

1+i

Step-by-step explanation:

To find the 8th roots of unity, you have to find the trigonometric form of unity.

1. Since $z=1=1+0\cdot i,$ then

$Rez=1,\\ \\Im z=0$

and

$|z|=\sqrt{1^2+0^2}=1,\\ \\\\\cos\varphi =\dfrac{Rez}{|z|}=\dfrac{1}{1}=1,\\ \\\sin\varphi =\dfrac{Imz}{|z|}=\dfrac{0}{1}=0.$

This gives you $\varphi=0.$

Thus,

$z=1\cdot(\cos 0+i\sin 0).$

2. The 8th roots can be calculated using following formula:

$\sqrt[8]{z}=\{\sqrt[8]{|z|} (\cos\dfrac{\varphi+2\pi k}{8}+i\sin \dfrac{\varphi+2\pi k}{8}), k=0,\ 1,\dots,7\}.$

Now

at k=0, $z_0=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 0}{8}+i\sin \dfrac{0+2\pi \cdot 0}{8})=1\cdot (1+0\cdot i)=1;$

at k=1, $z_1=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 1}{8}+i\sin \dfrac{0+2\pi \cdot 1}{8})=1\cdot (\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2})=\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2};$

at k=2, $z_2=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 2}{8}+i\sin \dfrac{0+2\pi \cdot 2}{8})=1\cdot (0+1\cdot i)=i;$

at k=3, $z_3=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 3}{8}+i\sin \dfrac{0+2\pi \cdot 3}{8})=1\cdot (-\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2})=-\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2};$

at k=4, $z_4=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 4}{8}+i\sin \dfrac{0+2\pi \cdot 4}{8})=1\cdot (-1+0\cdot i)=-1;$

at k=5, $z_5=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 5}{8}+i\sin \dfrac{0+2\pi \cdot 5}{8})=1\cdot (-\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2})=-\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2};$

at k=6, $z_6=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 6}{8}+i\sin \dfrac{0+2\pi \cdot 6}{8})=1\cdot (0-1\cdot i)=-i;$

at k=7, $z_7=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 7}{8}+i\sin \dfrac{0+2\pi \cdot 7}{8})=1\cdot (\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2})=\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2};$

The 8th roots are

$\{1,\ \dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2},\ i, -\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2},\ -1, -\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2},\ -i,\ \dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2}\}.$

Option C is icncorrect.

5 0

3 years ago