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jenyasd209 [6]
4 years ago
11

Day 1 Michael ran 5 miles day 2 Michael ran 2 miles day 3 Michael ran 7 miles day 4 Michael ran 3 miles how many more miles did

he run on day 3 than on day two? Determine if there’s extra or missing information
Mathematics
1 answer:
Nuetrik [128]4 years ago
6 0

Answer:

5 And there is extra info.

Step-by-step explanation:

Day 3= 7 miles.

Day 2=2 miles.

7-2= 5

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Step-by-step explanation:

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3 years ago
Find the greatest solution for x+y when x^2+y^2 = 7, x^3+y^3=10
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Answer:

4

Step-by-step explanation:

set

f(x,y)=x+y\\

constrain:

g(x,y)=x^2+y^2 = 7\\h(x,y)=x^3+y^3=10

Partial derivatives:

f_{x}=1\\f_{y} =1 \\g_{x}=2x \\g_{y}=2y\\h_{x}=3x^2 \\h_{y}=3y^2

Lagrange multiplier:

grad(f)=a*grad(g)+b*grad(h)\\

\left[\begin{array}{ccc}1\\1\end{array}\right]=a\left[\begin{array}{ccc}2x\\2y\end{array}\right]+b\left[\begin{array}{ccc}3x^2\\3y^2\end{array}\right]

4 equations:

1=2ax+3bx^2\\1=2ay+3by^2\\x^2+y^2=7\\x^3+y^3=10

By solving:

a=4/9\\b=-2/27\\x+y=4

Second mathod:

Solve for x^2+y^2 = 7, x^3+y^3=10 first:

x=\frac{1}{2} -\frac{\sqrt{13}}{2} \ or \ y=\frac{1}{2} +\frac{\sqrt{13}}{2} \\x=\frac{1}{2} +\frac{\sqrt{13}}{2} \ or \ y=\frac{1}{2} -\frac{\sqrt{13}}{2} \\x+y=-5\ or\ 1 \or\ 4

The maximum is 4

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3 years ago
What is the coefficient and the constant in 4+x=15?
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A grocer wants to make a 10-pound mixture of peanuts and cashews that he can sell for $4.75 per pound. If peanuts cost $4.00 per
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Answer:

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Step-by-step explanation:

8 0
3 years ago
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