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irina1246 [14]
3 years ago
7

Mr. Jones sent his kids to Mt. Olympus. He gave each of his 5 children money for the day that included money for 4 drinks, 3 san

dwiches, 2 treats, and $25 for the ticket in to the park.
If drinks (d) cost $1.50, sandwiches (s) cost $2, treats (t) costs $1, What is the total amount of money Mr. Jones gave to all five of his children?
Mathematics
1 answer:
mihalych1998 [28]3 years ago
6 0

Answer:

195

Step-by-step explanation:

4 drinks = 1.5 * 4 = 6.

3 sandwiches = 2 * 3 = 6

2 treats = 1 * 2 = 2

$6+$6+$2+$25 = 39

Multiply by 5 for each kid

39*5=195

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Serggg [28]

Answer:

y = 8x-3

Step-by-step explanation:

7 0
2 years ago
A scale model of a ramp is a right triangular prism as given in this figure. in the actual ramp, the triangular base has a heigh
kakasveta [241]

The surface area of the actual ramp including the underside is 16.8 ft²

The height of the actual ramp = 1.2 feet  

The height of the model = 6 cm

<h3>What is the surface area of a right triangular prism?</h3>

A right triangular prism is a 3-dimensional triangle with two congruent triangular faces and 3 rectangular faces that connect the triangular.

The surface area of a right triangular prism

= (Perimeter of the base × Length of the prism) + (2 × Base Area)

Scale factor = 1.2 feet / 6 cm = 0.2 ft/cm

Actual base = 16 cm × 0.2 ft/cm = 3.2 ft

convert the units

9 cm = 9 cm × 0.2 ft/cm = 1.8 ft

10 cm = 10 cm × 0.2 ft/cm = 2 ft

The surface area of a right triangular prism

= (Perimeter of the base × Length of the prism) + (2 × Base Area)

Surface area of actual ramp = 2(0.5 × 3.2 ft × 1.2 ft) + 2(2 ft × 1.8 ft) + (1.8 ft × 3.2 ft)

= 16.8 ft²

Hence, the surface area of the actual ramp including the underside is 16.8 ft²

Learn more about the area here:

brainly.com/question/25292087

3 0
3 years ago
Estimate : 1) 48% of 8 2) 3% of 119 3) 26% of 32 4) 76% of 280
zaharov [31]
1) 48% of 8=3.84 
2) 3% of 119=3.57
3) 26% of 32=8.32
4) <span>76% of 280=212.8

Hope this helps ya!</span>
7 0
3 years ago
A pole that is 3.1m tall casts a shadow that is 1.46m long. At the same time, a nearby building casts a shadow that is 36.75m lo
Mademuasel [1]
You have to find the angle of sunlight and the pole , which then cast a shadow
length of the pole is equal to 3.1m
creating a hypotenuse of 4.52m
the angle will be
[email protected] = opposite side / hypotenuse
= 1.46/4.52
= 0.32 that's 18.66 °
now for the building sin18.66° = opposite/hypotenuse
0.32 = 36.75/ hypotenuse
hypotenuse = 114.84 m
thus using Pythagoras theorem
114.84*114.84 = 36.75*36.75 + x^2
which comes around = 108.8 roughly 109 metres long
4 0
3 years ago
Geometry Homework Help Please?
kolbaska11 [484]
Ok what is the geometry u need help with
3 0
3 years ago
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