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Vesnalui [34]
3 years ago
10

A right pyramid with a square base has a base edge length of 24 feet and a slant height of 20 feet.

Mathematics
1 answer:
4vir4ik [10]3 years ago
8 0

Answer:

10.583

Step-by-step explanation:

If the height = h

Distance between the slant edge to center is 24 Cos 45

Therefore

h^{2}  = 20^{2}  - (24 Cos 45)^{2}

h = \sqrt{400-288} = 10.583

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Major axis = 25 + 3 = 28 feet


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1/2 minor axis = 21 / 2 = 10.5

1/2 major axis = 28 / 2 = 14

Using 3.14 for PI

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4 years ago
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Answer:

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Step-by-step explanation:

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\text{Distance Formula=}\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\\text{Radius=}\sqrt{(2-(-4))^2+(2-(-6))^2} \\=\sqrt{(2+4))^2+(2+6)^2}\\=\sqrt{6^2+8^2}\\=\sqrt{100}\\Radius=10

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Therefore, the equation of the circle is:

(x-(-4))^2+(y-(-6))^2=10^2\\\\(x+4)^2+(y+6)^2=100

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3 years ago
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