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Zielflug [23.3K]
3 years ago
11

What is the next cube number after 1

Mathematics
1 answer:
svet-max [94.6K]3 years ago
3 0
<span><span>Number          Cube
</span><span>1                 =1 × 1 × 1
</span><span>2                 8<span>=2 × 2 × 2</span></span></span>
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30 POINTS!!! What is the area of this figure? Enter your answer in the box
Elza [17]
Area of parallelogram: lw = 9(5)=45m
Area of triangle: 1/2bh = 1/2(9)(8) = 36m

So total area = 45+36=81m
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2 years ago
The estimated product of 20.7 and 9.18 after rounding both factors to the nearest whole number is
gogolik [260]
189 because 20.7 rounds to 21 and 9.18 rounds to 9
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What is the prime fractorization of 84
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3 years ago
Again ... Commute times in the U.S. are heavily skewed to the right. We select a random sample of 500 people from the 2000 U.S.
VladimirAG [237]

Answer:

We conclude that the mean commute time in the U.S. is less than half an hour.

Step-by-step explanation:

We are given that a random sample of 500 people from the 2000 U.S. Census is selected who reported a non-zero commute time.

In this sample the mean commute time is 27.6 minutes with a standard deviation of 19.6 minutes.

Let \mu = <u><em>mean commute time in the U.S..</em></u>

So, Null Hypothesis, H_0 : \mu \geq 30 minutes      {means that the mean commute time in the U.S. is more than or equal to half an hour}

Alternate Hypothesis, H_A : \mu < 30 minutes     {means that the mean commute time in the U.S. is less than half an hour}

The test statistics that would be used here <u>One-sample t-test statistics</u> as we don't know about population standard deviation;

                           T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean commute time = 27.6 minutes

            s = sample standard deviation = 19.6 minutes

            n = sample of people from the 2000 U.S. Census = 500

So, <u><em>the test statistics</em></u>  =  \frac{27.6 -30}{\frac{19.6}{\sqrt{500} } }  ~ t_4_9_9

                                       =  -2.738

The value of t test statistic is -2.738.

Since, in the question we are not given with the level of significance so we assume it to be 5%. <u>Now, at 5% significance level the t table gives critical values of -1.645 at 499 degree of freedom for left-tailed test.</u>

Since our test statistic is less than the critical value of t as -2.378 < -1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis.</u>

Therefore, we conclude that the mean commute time in the U.S. is less than half an hour.

4 0
3 years ago
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