In all you will need 48 square inches of gift wrap. 4*6= 24 and 24*2= 48
Hi there, (6z²+z-1)(9z-5)=(6z²+z+-1)(9z+-5)=(6z²)(9z)+(6z²)(-5)+(z)(9z)+(z)(-5)+(-1)(9z)+(-1)(-5)=54z³-30z²+9z²-5z-9z+5=54z³-21z²-14z+5. Therefore, the answer is 54z³-21z²-14z+5.
Procedure:
1) calculate the number of diferent teams of four members that can be formed (with the ten persons)
2) calculate the number of teams tha meet the specification (two girls and two boys)
3) Divide the positive events by the total number of events: this is the result of 2) by the result in 1)
Solution
1) the number of teams of four members that can be formed are:
10*9*8*7 / (4*3*2*1) = 210
2) Number of different teams with 2 boys and 2 girls = ways of chosing 2 boys * ways of chosing 2 girls
Ways of chosing 2 boys = 6*5/2 = 15
Ways of chosing 2 girls = 4*3/2 = 6
Number of different teams with 2 boys and 2 girls = 15 * 6 = 90
3) probability of choosing one of the 90 teams formed by 2 boys and 2 girls:
90/210 = 3/7
Answer:
663
Step-by-step explanation:
ratio of Malay = 5
ratio of Indian= 4
ratio of Chinese= 8
Total number of Indian + Chinese= 468
Total ratio= 5+4+8= 17
Let the total number of students= X
Ratio of India= 4/17 × X=
Ratio of Chinese= 8/17 × X=
Addition of ratio of both India and Chinese=
4X/17 + 8X/17= 468
(4X +8X)/17 = 468
12X/17= 468
X= 663
Hence, total number of students is 663
