Answer: Use a compass to measure the length of AB. Draw an arc from point B (or point A) with that distance. Extend line AB through that arc and label the intersection as point C. AC is twice the length of AB.
Answer:
exponential decay
Step-by-step explanation:
The midpoint, where the rest area is, will just be the average of the coordinates of Springfield and Columbus.
Rest Area=((1+7)/2, (-4+1)/2)
Rest Area=(4, -1.5)
The distance between the two cities can be found using the Pythagorean Theorem, which used in the manner is often referred to as the "distance" formula between two points.
d^2=(x2-x1)^2+(y2-y1)
d^2=(7-1)^2+(1--4)^2
d^2=36+25
d^2=61
d=√61 and we are told that each unit is equal to 5.38mi so the distance from Springfield to Columbus is:
D=5.38√61 mi
D≈42.02mi (to nearest hundredth of a mile)
A. 12x+y=6<span>B. −2x+y=6</span>