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Answer:
a^(2m) + 2 a^m b^ (n-1) + b^ ( 2n -2)
Step-by-step explanation:
( a^m + b^(n-1) )( a^m + b^(n-1) )
FOIL
first: a^m a^m = a^ 2m
outer: a^m b^ n-1
inner a^m b^ n-1
last : b^ n-1 b^ n-1 = b^ ( 2n -2)
Add together
a^(2m) + 2 a^m b^ (n-1) + b^ ( 2n -2)
H(X) = (x - 2)²(x + 4)(x - 1) has 3 zeroes, they are -4,2 and 1
Answer:
Check below for the answers
Step-by-step explanation:
Note: The options are not clearly expressed but below are the correct expressions for the trigonometric identities stated in the options.
Using the SOHCAHTOA principle
sin θ = Opposite / Hypotenuse
tan θ = opposite / Adjacent
Cot θ = 1 / tan θ = Adjacent / Opposite
cos θ = Adjacent / Hypotenuse