300 miles is equal to how many yards
= 528000
Hope this helps!
It would either be 21 or 25 as they both have the same amount of factors :)
Answer:
The crop yield increased by 9 pounds per acre from year 1 to year 10.
Step-by-step explanation:
To solve this we are using the average rate of change formula:
, where:
is the second point in the function
is the first point in the function
is the function evaluated at the second point
is the function evaluated at the first point
We know that the first point is 1 year and the second point is 10 years, so
and
. Replacing values:
![Av=\frac{-(10)^2+20(10)+50-[-(1)^2+20(1)+50]}{10-1}](https://tex.z-dn.net/?f=Av%3D%5Cfrac%7B-%2810%29%5E2%2B20%2810%29%2B50-%5B-%281%29%5E2%2B20%281%29%2B50%5D%7D%7B10-1%7D)
![Av=\frac{-100+200+50-[-1+20+50]}{9}](https://tex.z-dn.net/?f=Av%3D%5Cfrac%7B-100%2B200%2B50-%5B-1%2B20%2B50%5D%7D%7B9%7D)
![Av=\frac{150-[69]}{9}](https://tex.z-dn.net/?f=Av%3D%5Cfrac%7B150-%5B69%5D%7D%7B9%7D)



Since
represents the number of pounds per acre and
the number of years, we can conclude that the crop yield increased by 9 pounds per acre from year 1 to year 10.
remember to use SOH CAH TOA. THE SOLUTION THAT I GOT CAME OUT AS 15/8
Answer:
68
Step-by-step explanation:
We let the random variable X denote the height of students of the college. Therefore, X is normally distributed with a mean of 175 cm and a standard deviation of 5 centimeters.
We are required to determine the percent of students who are between 170 centimeters and 180 centimeters in height.
This can be expressed as;
P(170<X<180)
This can be evaluated in Stat-Crunch using the following steps;
In stat crunch, click Stat then Calculators and select Normal
In the pop-up window that appears click Between
Input the value of the mean as 175 and that of the standard deviation as 5
Then input the values 170 and 180
click compute
Stat-Crunch returns a probability of approximately 68%