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Whitepunk [10]
2 years ago
14

Why s orbital does not contain degenerate orbital​

Chemistry
1 answer:
Juliette [100K]2 years ago
3 0
There’s no other degenerate s orbital because the there can be only one s orbital for any value of n.
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Your class goes on a field trip to observe drilling machinery. The geologists at the drill site show you displays of drilled roc
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the answer is petroleum

Explanation:

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What is Data Analysis?
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2 years ago
Why does a gold isotope, with an atomic number of 79, require more neutrons to be stable than a sodium isotope, with an atomic n
Leya [2.2K]

Here’s a simplified explanation.

The <em>protons</em> in the nucleus <em>repel each other</em>. The <em>neutrons provide the “glue”</em> that holds the nucleus together and prevents it from flying apart.

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A <em>neon atom</em> has 10 protons. There are three stable isotopes, with 10, 11, and 12 neutrons.

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If there are more than 12 neutrons, the average p-n distance is great enough that the glue has again become too weak.

<em>Gold</em> has one stable isotope. It contains 79 protons and 118 neutrons.

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8 0
3 years ago
Is decay pool or flux
mash [69]

Answer:

A single carbon pool can often have several fluxes both adding and removing carbon simultaneously. For example, the atmosphere has inflows from decomposition (CO2 released by the breakdown of organic matter), forest fires and fossil fuel combustion and outflows from plant growth and uptake by the oceans.

Explanation:

7 0
1 year ago
The heat of vaporization of 1–pentanol is 55.5 kJ/mol, and its entropy of vaporization is 148 J/K•mol. What is the approximate b
tensa zangetsu [6.8K]

Answer:

375 K

Explanation:

Using the experssion shown below as:

\Delta G^0=\Delta H^0_{vap}-T\Delta S^0_{vap}

At vaporization point, the liquid and the gaseous phase is in the equilibrium.

Thus,

\Delta G^0=0

So,

Delta H^0_{vap}=T\Delta S^0_{vap}

Given that:

Delta H^0_{vap}=55.5\ kJ/mol

Also, 1 kJ = 10³ J

So,

Delta H^0_{vap}=55500\ J/mol

\Delta S^0_{vap}=148\ J/K.mol

So, temperature is :

T=\frac{Delta H^0_{vap}}{\Delta S^0_{vap}}

T=\frac{55500}{148}

<u>T= 375 K</u>

3 0
3 years ago
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